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2 years ago

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The melting point of gallium metal is 29.76⁰C. If a piece of gallium is sliced into three parts, the melting point of each part

will be what A: higher than 29.76⁰C. B: 29.76⁰C. C: lower than 29.76⁰C

1 answer:

Ahat [919]2 years ago

7 0

Answer:

itd be B because the melting point is 29.76 no matter the size

Explanation:

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A sample of iron metal is placed in a graduated cylinder. it is noted that 10.4 ml of water is displaced by the iron. the iron i

Pavel [41]

<h3>Answer:</h3>

162.43 g of FeCl₂

<h3>Explanation:</h3>

Step 1: Calculate mass of Fe;

As,

Density = Mass ÷ Volume

Or,

Mass = Density × Volume

Where Volume is the volume of water displaced = 10.4 mL

Putting values,

Mass = 7.86 g.mL⁻¹ × 10.4 mL

Mass = 81.744 g of Fe

Step 2: Calculate amount of FeCl₂;

The balance chemical equation is as follow,

Fe + 2 HCl → FeCl₂ + H₂ ↑

According to this equation,

55.85 g (1 mol) Fe produced = 110.98 g (1 mol) of FeCl₂

So,

81.744 g Fe will produce = X g of FeCl₂

Solving for X,

X = (81.744 g × 110.98 g) ÷ 55.85 g

X = 162.43 g of FeCl₂

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3 years ago

Use dimensional analysis to convert 14.5mi/hr to km/s

Liula [17]

Answer:

0.006 48 km/s

Explanation:

1. Convert miles to kilometres

14.5 mi × (1.609 km/1 mi) = 23.33 km

2. Convert hours to seconds

1 h × (60 min/1h) × (60 s/1 min) = 3600 s

3. Divide the distance by the time

14.5 mi/1 h = 23.3 km/3600 s = 0.006 48 km/s

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3 years ago

If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.

kicyunya [14]

Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

$CH_{3}COOH \ \textless \ ---\ \textgreater \ H^{+} + CH_{3}COO^{-}$

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> $[H^{+}]$ = $10^{-2.88}$ = 0.001 $moldm^{-3}$

The change in Concentration Δ $[CH_{3}COOH]$ = 0.001 $moldm^{-3}$

  CH3COOH H+ CH3COOH
Initial   $moldm^{-3}$      $x$ 0 0

Change $moldm^{-3}$ -0.001 +0.001 +0.001

Equilibrium $moldm^{-3}$ $x$ - 0.001 0.001 0.001


Since the $k_{a}$ value is so small, the assumption
$[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium}$ can be made.

$k_{a} = [tex]= 1.8*10^{-5} = \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} = \frac{0.001^{2}}{x}$

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps!

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3 years ago

svp [43]

Because more than one substance was released (following a color change signifying a chemical reaction), the sample was indeed, a compound.

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3 years ago

Read 2 more answers

Can anyone fill in the answers?

Arte-miy333 [17]

Hi, P.S. The atomic number will always be the same as the number of protons...

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2 years ago