Answer:
Option (2) At equilibrium, there is a much higher concentration of products than reactants.
Explanation:
The equilibrium constant for a reaction is simply the ratio of the concentration products raised to their mole ratio divided by the concentration of the reactants raised to their mole ratio.
If the equilibrium constant is close to 1 or 1, it means the concentration of the reactants and products are almost the same. But if the equilibrium constant is large as in the case of the question given above, it means that at equilibrium, the concentration of the products are higher than that of the reactants.
What we want to measure is the taste of coffee.
The following were kept constant during the experimental investigation:
The type of coffee,
The type of percolator,
The same amount and type of water,
The same perking time,
The same electrical sources.
Because these items were kept constant, they are not expected to influence the outcome of the experimental investigation.
Define:
y = the metric used to measure the taste of coffee
x = amount of coffee grounds used for the taste experiment.
Therefore the relationship that arises from the experiment is
y = y(x).
Because x is controllable and is varied during the experiment, it is the independent variable.
Because the measured value of y depends on x, therefore y is the dependent variable.
Answer:
The taste of coffee is the dependent variable.
The amount of coffee grounds used is the independent variable.
B. The partial pressure of N2 is 101 kPa
<h3>Further explanation</h3>
Given
volume = 22.4 L
1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C
Required
Total pressure and partial pressure
Solution
Ideal gas law :
PV = nRT
n total = 3 mol
T = O °C + 273 = 273 K
P = nRT/V
P = 3 x 0.08205 x 273 / 22.4
P total = 3 atm = 303,975 kPa
P Nitrogen = 1/3 x 303.975 = 101.325 kPa
P Hydrogen = 2/3 x 303.975 = 202.65 kPa
Mass C₆H₈O₇ : 0.531484 g
<h3>Further explanation</h3>
Reaction
3NaHCO₃ (aq) + C₆H₈O₇ (aq) → 3 CO₂ (g) + 3 H₂O (l) + Na₃C₆H₅O₇ (aq)
MW NaHCO₃ : 84 g/mol
mass NaHCO₃ : 7.10² mg=0.7 g
mol NaHCO₃ :
mol C₆H₈O₇ :
MW C₆H₈O₇ : 192 g/mol
mass C₆H₈O₇ :
