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Pani-rosa [81]
2 years ago
10

Will mark Brainliest!

Physics
2 answers:
DENIUS [597]2 years ago
8 0
I think it’s A protons .. hope this helps
Sergeeva-Olga [200]2 years ago
8 0
A) protons.

hope this helps :)
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The intensity is defined as the ratio between the power emitted by the source and the area through which the power is calculated:
I= \frac{P}{A} (1)
where
P is the power
A is the area

In our problem, the intensity is I=6.0 \cdot 10^{-10} W/m^2. At a distance of r=6.0 m from the source, the area intercepted by the radiation (which propagates in all directions) is equal to the area of a sphere of radius r, so:
A=4 \pi r^2 = 4 \pi (6.0 m)^2 = 452.2 m^2

And so if we re-arrange (1) we find the power emitted by the source:
P=IA = (6.0 \cdot 10^{-10}W/m^2)(452.2 m^2)=2.7 \cdot 10^{-7} W
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