Answer:
A.Gravity acts to pull the object down
D.The object’s inertia carries it forward.
E.The path of the object is curved.
Explanation:
The motion of a projectile consists of two independent motions:
- A uniform motion along the horizontal direction, with constant horizontal speed
- A vertical motion with constant acceleration of g = 9.8 m/s^2 downward (acceleration due to gravity), due to the presence of the force of gravity, so the vertical velocity changes (increases in the downward direction)
As a result, the combined motion of the projectile has a curved trajectory (parabolic, more specifically). So the following options are correct:
A.Gravity acts to pull the object down --> gravity acts along the vertical direction
D.The object’s inertia carries it forward. --> there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal motion continues with constant speed
E.The path of the object is curved
It would be 3.15 in meters
Answer:
8.6 m/s
Explanation:
We can find the final velocity of the dog by using the following SUVAT equation:

where
u is the initial velocity
a is the acceleration
d is the distance covered
For the dog in the problem, we have
u = 1.5 m/s

And the distance covered is
d = 3.0 m
Therefore, we can re-arrange the equation to find the final velocity, v:

Answer:
A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.
B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.
[D] = 0.90 M
Explanation:
With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.
This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.
- The first attached image contains the correct question.
- The solution to part A is presented in the second attached image.
- The solution to part B is presented in the third attached image.
Answer:
It is frequently stated that the value of the acceleration due to gravity at the pole is larger than at the equator because the poles are closer to the center of the earth due to the earth's oblateness. ... The measured value is larger because the earth's density is not uniform but increases toward the center.