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tigry1 [53]
3 years ago
15

Which of the following examples does not make use of total internal reflection?

Physics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

laser pointer does not make use of total internal reflection

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What criteria do astronomers use to classify an object as a planet
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Orbits a Star.... gravity makes it spherical.
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3 years ago
What is the mass of a person who has a weight of 647N?<br> Will mark brainliest if u help me!!
Stels [109]

Answer: i think thats the answer

≈

40.8

kg

Explanation:

Well, assuming the boy is on Earth, then the gravitational acceleration is approximately

9.8

m/s

2

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So, we get:

m

=

W

g

=

400

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9.8

m/s

2

≈

40.8

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7 0
3 years ago
When carrying extra weight, the space formed between the top of your head and the two axles of the motorcycle is referred to as
Dafna11 [192]
When carrying extra weight, the space formed between the top of your head and the two axles of the motorcycle is called "load triangle". Because of a motorcycle's size and weight<span> and the fact that it has only two wheels, how to carry extra load is very important. One has to make sure that they are keeping the weight low and close to the middle of the motorcycle and keep the load evenly from side to side. Heavier items should be in the "load triangle".</span><span> </span>
3 0
3 years ago
A car is moving with speed 60 m/s and acceleration 4 m/s2 at a given instant. (a) using a second-degree taylor polynomial, estim
pantera1 [17]

Answer:

Explanation:

Using second degree taylor polynomials

let S(t) be position function and set S(0)=0

where S(0) is the initial position

Then v(t) = S^i(t) and a(t)=S^{ii}(t)

we have v(0) = 60m/s, a(0) = 4m/s^2

so T_{2}(t) =S(0)+v(0)t+\frac{a(0)}{2} t^2\\\\\\=0+60t+\frac{4}{2} t^2\\\\T_{2}(t)=60t+2t^2\\\\S(1)=T_{2}(1)=60+2=62m

b.) yes

6 0
3 years ago
The nonreflective coating on a camera lens with an index of refraction of 1.21 is designed to minimize the reflection of 570-nm
lord [1]

Answer: 117.8 nm

Explanation:

Given,

Nonreflective coating refractive index : n = 1.21

Index of refraction: n_0 = 1.52

Wave length of light = λ = 570 nm = 570\times10^{-9}\ m

\text{ Thickness}=\dfrac{\lambda}{4n}

=\dfrac{570\times10^{-9}\ m}{4\times1.21}\\\\\approx\dfrac{117.8\times 10^{-9}\ m}{1}\\\\=117.8\text{ nm}

Hence, the minimum thickness of the coating that will accomplish= 117.8 nm

5 0
3 years ago
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