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DiKsa [7]
3 years ago
12

8. A roller coaster's velocity at the top of a hill is 10 m/s. It reaches the bottom of the hill with a

Physics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

is   8 m/s2

Explanation:

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A transverse, travelling wave on a chord is represented by = 0.22sin (5.6 + 34) where and are in meters and is in seconds. For t
Neko [114]

Answer:

A)  1.122 m

B)  5.4 hertz

C)  6.06 m/s ( towards negative  x axis )

D)  0.22

E)  max speed = amplitude * 34

                  = 0.22 * 34 = 7.48

  minimum speed ( speed at rest ) = 0

Explanation:

The travelling wave = D = 0.22sin ( 5.6x + 34t)

this wave is represented in the form : D = Asin ( kx + wt)

A) wavelength

k = 2\pi / v

v = wavelength

k = 5.6

therefore wavelength ( v ) from the equation = 2\pi / 5.6 = 1.122 m

B ) frequency

w = 2\pif

w = 34

f = frequency

therefore f = w / 2\pi  = 34 / 2\pi = 5.4 hertz

C ) velocity

speed = f v

v = 5.4 * 1.122 = 6.06 m/s ( towards negative  x axis )

D) amplitude

A = 0.22

E ) maximum and minimum speeds of particles on the chord

max speed = amplitude * 34

                  = 0.22 * 34 = 7.48

minimum speed ( speed at rest ) = 0

5 0
3 years ago
White Lake was contaminated with the Chemical Complany dispersing their waste in the lake. Eventually, they were forced to stop
melamori03 [73]

Answer:

White Lake was contaminated with the Chemical Complany dispersing their waste in the lake. Eventually, they were forced to stop dumping it into the lake

7 0
3 years ago
How much heat is absorbed by a 27g iron skillet when its temperature rises from 13oC to 23oC?
solniwko [45]
The equation for heat would be q = m*Delta T* S

Where q = the heat absorbed in joules
m = mass 
Delta T = change in temperature
s = specific heat capacity of the material

for iron s = 0.450

Delta T = 23 - 13 = 10 degrees Celsius

m is given as 27 grams.

q = 27 * 10 * 0.450 = 121.5 joules  

You may need to round the answer depending on what the teacher is looking for.
8 0
4 years ago
A civil engineer plans to design a curved ramp such that a car may not have to rely on friction to round the curve without skidd
Delicious77 [7]

Answer:\theta =\tan ^{-1}(\frac{v^2}{gR})

Explanation:

let \theta be the inclination at which curve is tilted

v is the speed of car and R is the radius of curve

m is the mass of car

Suppose R is the reaction offered by road to car

Resolving R in x and y direction we get

R\cos \theta will balance weight and R\sin \theta will provide the necessary centripetal Force

thus R\sin \theta =\frac{mv^2}{R}  ------------1

R\cos \theta =m g  ----------------2

Divide 1 & 2 we get

\frac{R\sin \theta }{R\cos \theta }=\frac{mv^2}{mgR}

\tan \theta =\frac{v^2}{gR}

\theta =\tan ^{-1}(\frac{v^2}{gR})                                      

8 0
3 years ago
May I please get some help?
morpeh [17]

Answer:

13.4 m/s

Explanation:

Write down what you have, so:

V0=8 m/s

a=2.7 m/s^2

t=2 seconds

We are trying to find final velocity, so we will use vf = v0 + at

From there, we plug in the given values.

vf = 8 m/s + (2.7 m/s^2 x 2 seconds)

vf = 13.4 m/s

5 0
4 years ago
Read 2 more answers
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