How far does a car travel in 30.0 s while its velocity is changing from 50.0 km/h to 80.0 km/h at a uniform rate of acceleration
1 answer:
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Answer:
Ring v² = gh
solid wheel (cylinder) v² = 4/3 gh
Explanation:
Let's use conservation of energy to find the speed of the wheels at the bottom of the hill.
starting point. Point before starting movement
Em₀ = mgh
final point. At the bottom of the hill
Em_f = K = ½ m v² + ½ I w²
energy is conserved
Emo = Em_f
mgh = ½ m v² + ½ I w²
angular and linear velocity are related
v = w r
we substitute
mgh = ½ m v² + ½ I v² / r²
mgh = ½ (m + I / r²) v²
v² =
the moments of inertia are tabulated
Ring
I = mr²
v² = 2 m g h / (m + m)
v² = gh
solid wheel (cylinder)
I = ½ m r²
v² = 2m gh / (m + m / 2)
v² = 4/3 gh
We can see that due to the difference in the moment of inertia of each body it is different, the solid wheel has more speed when it reaches the lower part of the ramp
Answer:
C. Copper
Explanation:
F = Force on string
= Intial length of string
A = Area of string
E = Young's modulus of material
Change in length is given by
It can be seen that the change in length is inversely proportional to the Young's modulus of the material.
Here
So, copper will stretch the least.