How far does a car travel in 30.0 s while its velocity is changing from 50.0 km/h to 80.0 km/h at a uniform rate of acceleration
1 answer:
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Answer:
755 x 10⁻⁷ m
Explanation:
D = distance of screen
=2. m
d is width of slit = ?
wave length λ = 566 nm
Width of central maxima = 2 λD /d
= 3.00 x 10⁻² =2 λD /d
= 754.67 x 10⁻⁷ m .
= 755x 10⁻⁷ m
