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3 years ago

What happens to the magnitude of the gravitational force as the bodies become more massive?

1 answer:

8 0

The formula for calculating gravitational force between any two objects is givn by:
$F=G* \frac{ m_{1}*m_{2} }{ r^{2} }$

Here:
G = universal gravitational constant; $6.67* 10^{-11} m^{3} kg^{-1} s^{-2}$
m1 = mass of first object
m2 = mass of second object
r = distance between two objects

Masses of objects is located in a numerator of a fraction. This means that increasing the mass of any (or both) object increases the value of a fraction. This leads to increase of right side. This means that as mass increases so does the gravitational force.

If the distance was increasing this would mean that the force decreases because distance is located in a denominator of a fraction.

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How efficient are the small and large scale solar-power systems used in individual homes and industrial settings?

alexandr402 [8]

Answer:

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2 years ago

What’s the kinetic energy of the roller coaster at the top and bottom of the hill? Use . A kiddie roller coaster car has a mass

serious [3.7K]

K.E1=1/2×100×3²
=50×9
=450J
K.E2=1/2×100×36
=50×36
=1800J

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3 years ago

Read 2 more answers

Explain why cooler stars are red and hotter stars are blue

sergey [27]

More cool stars produce much of their light in the red part of the spectrum, so you see them, and bam, the color red. More hot stars, however, produce much more of their light in the green and or yellow spectrums, with much more tinier amounts of red / blue. This balance of the colors, your eye, sees simply as white. The more hot something is, the greater frequency of radiation it produces! Blue light has a higher frequency than red light, so the stars that glow red are cooler, than the stars that glow blue. :)

Hope this helped!

8 0

3 years ago

What is the driving force of charge around a circuit

Virty [35]

A force of charge that drive around a circuit is call electeons

5 0

3 years ago

If the initial velocity of a ball is sent straight upward at 10.5m/s from the ground what will its final velocity be when it hit

Shalnov [3]

Answer: -10.08 m/s

Explanation:

Here we only need to analyze the vertical problem.

When the ball is in the air, the only force acting on it will be the gravitational force, this means that the acceleration of the ball, is equal to the gravitational acceleration, then:

a(t) = -9.8m/s^2

Where the negative sign is because gravity pulls the ball down.

To get the velocity equation we need to integrate over time, we get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity, here it is v0 = 10.5 m/s

Then the velocity equation is:

v(t) = (-9.8m/s^2)*t + 10.5 m/s

To get the position equation, we need to integrate again over time, we get:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t + p0

Where p0 is the initial position, we know that the ball is sent upward from the ground, so p0 = 0m

Then the position equation is:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

Now we need to find the value of t such that the position is equal to zero (this means that the ball hits the ground again).

Then we need to solve:

p(t) = 0 = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

If we divide both sides by t, we get:

0 = (1/2)*(-9.8m/s^2)*t + (10.5 m/s)

Now we can solve it:

(1/2)*(9.8m/s^2)*t = 10.5 m/s

t = (10.5 m/s)/((1/2)*(9.8m/s^2)) = 2.14 s

This means that after 2.14 seconds, the ball will hit the ground again.

The velocity of the ball when it hits the ground is equal to:

v(2.14s) = (-9.8m/s^2)*2.14s + 10.5 m/s = -10.08 m/s

3 0

3 years ago