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Ilia_Sergeevich [38]
3 years ago
11

What happens to the magnitude of the gravitational force as the bodies become more massive?

Physics
1 answer:
Sever21 [200]3 years ago
8 0
The formula for calculating gravitational force between any two objects is givn by:
F=G* \frac{ m_{1}*m_{2} }{ r^{2} }

Here:
G = universal gravitational constant; 6.67* 10^{-11}  m^{3}  kg^{-1}  s^{-2}
m1 = mass of first object
m2 = mass of second object
r = distance between two objects

Masses of objects is located in a numerator of a fraction. This means that increasing the mass of any (or both) object increases the value of a fraction. This leads to increase of right side. This means that as mass increases so does the gravitational force.

If the distance was increasing this would mean that the force decreases because distance is located in a denominator of a fraction.
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The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
Sonja [21]

Answer:

10.16 degrees

Explanation:

Apply Snells Law for both wavelenghts

\(n_{1}sin\theta_{1} = n_{2}sin\theta_{2}\)

For red

(1.620)(sin 25.5) = (1)(sin r)

For red, the angle is 35.45degrees

For violet

(1.660)(sin 25.5) = (1)(sin v)

For violet, the angle is 45.6 degrees

The difference is 45.6- 35.45 = 10.16 degrees

3 0
3 years ago
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Angelina_Jolie [31]
I am very sorry I don’t know
7 0
3 years ago
The temperature of a gas is increased by 10degree Celsius. what is the corresponding change on Fahrenheit scale?​
Grace [21]

On a Fahrenheit thermometer, the gas becomes 18 degrees warmer.

8 0
3 years ago
A material through which electronics do NOT easily flow is
ziro4ka [17]
Resistor. The answer is a resistor. They do not transmit electricity. 
6 0
2 years ago
A basketball player grabbing a rebound jumps 76.0 cm vertically. How much total time (ascent and descent) does the player spend
Viefleur [7K]

a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how

long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175

s this is the time to fall from the top; it would take the same time to travel

upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175

= 0.35s

b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice

to solve this problem the time it takes to fall the final 0.13 m is: time it

takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to

fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it

takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m

is then twice this, or 0.08s

5 0
3 years ago
Read 2 more answers
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