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dsp73
2 years ago
11

What ate the effects of gravitional force​

Physics
1 answer:
faust18 [17]2 years ago
4 0

Answer:

Gravity is what holds the planets in orbit around the sun and what keeps the moon in orbit around Earth. The gravitational pull of the moon pulls the seas towards it, causing the ocean tides. Gravity creates stars and planets by pulling together the material from which they are made.

Explanation:

I was learning about this in class

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If the wavelength is doubled what happens to the period​
Temka [501]

Answer: Wave speed may equal frequency*wavelength. Yet doubling the frequency only halves the wavelength; wave speed remains the same. To change the wave speed, the medium would have to be changed. 24. What are some simple steps I can take to protect my privacy online? Many people ... So if you double the frequency and keep the speed constant, the wavelength halves to give the same speed with the doubled frequency. 3.8k views ... The period of a note is 0.3 seconds and the speed of sound in air is 340 m/s. So if you double the frequency and keep the speed constant, the wavelength halves to give the same speed with the doubled frequency. What is the period of a wave if the wavelength is 100m and the speed is 200 m/s? ... If you move towards a light source, the wavelength decreases.

Explanation:

3 0
3 years ago
Help please due by 3:00
FrozenT [24]

Answer:

  zero

Explanation:

Acceleration is a measure of the rate of change of velocity. If the velocity is unchanging, its rate of change is zero.

The acceleration is zero.

8 0
3 years ago
PLEASE HELP!!
Klio2033 [76]

Answer:

28.15

Explanation:

the ateps is in the photo

6 0
3 years ago
Point charges of 21.0 μC and 47.0 μC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el
rewona [7]

Answer:

a) x = 0.200 m

b)E = 3.84*10^{-4} N/C

Explanation:

q_1 = 21.0\mu C

q_1 = 47.0\mu C

DISTANCE BETWEEN BOTH POINT CHARGE = 0.5 m

by relation for electric field we have following relation

E = \frac{kq}{x}^2

according to question E = 0

FROM FIGURE

x is the distance from left point charge where electric field is zero

\frac{k21}{x}^2 = \frac{k47}{0.5-x}^2

solving for x we get

\frac{0.5}{x} = 1+ \sqrt{\frac{47}{21}}

x = 0.200 m

b)electric field at half way mean x =0.25

E =\frac{k*21*10^{-6}}{0.25^2} -\frac{k*47*10^{-6}}{0.25^2}

E = 3.84*10^{-4} N/C

6 0
3 years ago
Read 2 more answers
When driving at night, only use your high-beam headlights___
zzz [600]

Answer:

B

Explanation:

While answer C may sound correct, Answer B is makes more sense. We know you cant use High-beam lights when u cant see ongoing traffic because it could affect the other driver coming across from you. Its good to use it when legal and safe, but in that term I still don't believe there's no reason for HIGH-beamed. That's this leaves B, when you are on u lighted streets.

6 0
3 years ago
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