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Tomtit [17]
3 years ago
9

Determine the number of moles in 4.00x10^2 g of cesium iodide

Chemistry
1 answer:
Tema [17]3 years ago
3 0
<span>Given the value for S2- as 3.42 x 10-17 M find the value of Ag+. (2:1 ratio). Ag2S W ... 4.00 x10 M ... First,calculate the number of moles in solution by multiplying volume and .... To find the number of grams of oxygen: 100 – (31.7 + 5.30) = 63.0.</span><span>
</span>
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In step 2, of the experiment, the procedure uses 3.0M NaOH. However, the student notices that the only solution of NaOH is conce
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Answer:

We need 78.9 mL of the 19.0 M NaOH solution

Explanation:

Step 1: Data given

Molarity of the original NaOH solution = 19.0 M

Molarity of the NaOH solution we want to prepare = 3.0 M

Volume of the NaOH solution we want to prepare = 500 mL = 0.500 L

Step 2: Calculate volume of the 19.0 M NaOH solution needed

C1*V1 = C2*V2

⇒with C1 = the concentration of the original NaOH solution = 19.0 M

⇒with V1 = the volume of the original NaOH solution = TO BE DETERMINED

⇒with C2 = the concentration of the NaOH solution we want to prepare = 3.0 M

⇒with V2 = the volume  of the NaOH solution we want to prepare = 500 mL = 0.500 L

19.0 M * V2 = 3.0 M * 0.500 L

V2 = (3.0 M * 0.500L) / 19.0 M

V2 = 0.0789 L

We need 0.0789 L

This is 0.0789 * 10^3 mL = 78.9 mL

We need 78.9 mL of the 19.0 M NaOH solution

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3 years ago
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