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marissa [1.9K]
3 years ago
11

The magnitude of the magnetic field at a certain distance from a long, straight conductor is represented by B. What is the magni

tude of the magnetic field at twice the distance from the conductor?
A. At twice the distance, the magnitude of the field is 4B.
B. At twice the distance, the magnitude of the field is 2B.
C. At twice the distance, the magnitude of the field is B/2.
D. At twice the distance, the magnitude of the field is B/4.
E. At twice the distance, the magnitude of the field remains equal to B.

Physics
2 answers:
Oksanka [162]3 years ago
5 0

Explanation:

Below is an attachment containing the solution

den301095 [7]3 years ago
4 0

Answer:

Option C is correct.

The magnitude of the field is reduced to half at twice the distance,

Explanation:

The magnetic field produced in a long, straight conductor carrying a current I at distance r is given by

B = μ₀I/2πr

Where μ₀ is the constant permeability of free space.

If we increase the distance by twice then

B = μ₀I/2π(2r)

B = μ₀I/2πr(2)

B = B/2

Therefore, the magnitude of magnetic field is reduced by B/2 at twice the distance.

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Answer:

The funda mental frequency of the original tube is 182Hz.

Explanation:

See the attachment for the calculation steps.

In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.

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The details of calculation can be found below in the attachment.

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Vikentia [17]

Answer:

Explanation:

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Answer:

false

Explanation:

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7 0
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AleksandrR [38]

Answer:The frequency of the echo is slightly decreased

Explanation:

Given

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