The magnitude of the magnetic field at a certain distance from a long, straight conductor is represented by B. What is the magni
tude of the magnetic field at twice the distance from the conductor?
A. At twice the distance, the magnitude of the field is 4B.
B. At twice the distance, the magnitude of the field is 2B.
C. At twice the distance, the magnitude of the field is B/2.
D. At twice the distance, the magnitude of the field is B/4.
E. At twice the distance, the magnitude of the field remains equal to B.
A. At twice the distance, the magnitude of the field is 4B.
B. At twice the distance, the magnitude of the field is 2B.
C. At twice the distance, the magnitude of the field is B/2.
D. At twice the distance, the magnitude of the field is B/4.
E. At twice the distance, the magnitude of the field remains equal to B.
2 answers:
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Answer:
The resistance is
Explanation:
Given that,
Diameter of tube = 8.5 mm
Length = 8 cm
Resistivity = 2.5 m
We need to calculate the resistance
The resistance is equal to the product of the resistivity and length divided by the area of cross section .
In mathematical form,
Where, =resistivity
l = length
A = area of cross section
Put the value into the formula
Hence, The resistance is
The ratio of the maximum photoelectron kinetic energy to the work function will be 3:1.
<h3 /><h3>What is the photoelectric effect?</h3>When a medium receives electromagnetic radiation, electrostatically charged particles are emitted from or inside it.
The emission of ions from a steel plate when light falls on it is a common definition of the effect. The substance could be a solid, liquid, or gas; and the released particles could be protons or electrons.
A particular metal emits photoelectrons when exposed to light with energy three times its work function:
The ratio of the maximum photoelectron kinetic energy to the work function will be;
Hence, the ratio of the maximum photoelectron kinetic energy to the work function will be 3:1.
To learn more about the photoelectric effect refer to the link;
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