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notka56 [123]
3 years ago
14

When driving at night switch to low-beams whenever you come within ___ ft of an oncoming vehicle.

Physics
2 answers:
Goshia [24]3 years ago
8 0

Answer:

500 ft

Explanation: One must dim their high-beam lights when the oncoming vehicle is  500 ft away so that the oncoming driver can look clearly and drive safely. High beam light should be used at night to drive safely when one is not able to see ahead of the road clearly. Even for the most experienced drivers low visibility is an issue.

Ainat [17]3 years ago
3 0
B. 500ft.  If you are driving at night with high beams on you must dim them within 500 feet of an oncoming vehicle.
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Most likely analog signal.
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A race-car driver achiveved a speed of speed of m/s in 14 seconds after taking off from ready at the starting line . What was th
vladimir2022 [97]
Average acceleration = (change in speed) / (time for the change)

Average acceleration =

(speed at the end of the 14 seconds) / (14 seconds)
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3 years ago
Children learn to resolve conflicts from surrounding adults.
sergij07 [2.7K]

Answer:

It is true that children learn to resolve conflicts from surrounding adults.

Explanation:

  • The environment where the children are raised reflects their decision making abilities and conflicts handling power.
  • Children are the best imitators of the adult around them. From all the activities adults perform around them, they learn that and apply in their life.
  • So it is always best to take care of our activities that we perform in front of our children.
4 0
3 years ago
In an arcade game a 0.099 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releas
Sonja [21]

Answer:

The speed of disk is 1.98 \frac{m}{s}

Explanation:

Given:

Mass of m = 0.099 kg

Spring constant k = 244 \frac{N}{m}

Compression of spring x = 4 \times 10^{-2} m

From energy conservation theorem,

Spring potential energy converted into kinetic energy,

   \frac{1}{2} m v^{2} = \frac{1}{2} k x^{2}

  v = \sqrt{\frac{k x^{2} }{m} }

  v = \sqrt{\frac{244 \times 16 \times 10^{-4} }{0.099} }

  v = 1.98 \frac{m}{s}

Therefore, the speed of disk is 1.98 \frac{m}{s}

8 0
3 years ago
1) You slam on the brakes of your car in a panic, and skid a certain distance on a straight level road. If you had been travelin
aleksandr82 [10.1K]

Answer:

d = 4 d₀o

Explanation:

We can solve this exercise using the relationship between work and the variation of kinetic energy

         W = ΔK

In that case as the car stops v_f = 0

the work is

          W = -fr d

we substitute

          - fr d₀ = 0 - ½ m v₀²

           d₀ = ½ m v₀² / fr

now they indicate that the vehicle is coming at twice the speed

          v = 2 v₀

using the same expressions we find

           d = ½ m (2v₀)² / fr

           d = 4 (½ m v₀² / fr)

           d = 4 d₀o

3 0
3 years ago
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