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notka56 [123]
3 years ago
14

When driving at night switch to low-beams whenever you come within ___ ft of an oncoming vehicle.

Physics
2 answers:
Goshia [24]3 years ago
8 0

Answer:

500 ft

Explanation: One must dim their high-beam lights when the oncoming vehicle is  500 ft away so that the oncoming driver can look clearly and drive safely. High beam light should be used at night to drive safely when one is not able to see ahead of the road clearly. Even for the most experienced drivers low visibility is an issue.

Ainat [17]3 years ago
3 0
B. 500ft.  If you are driving at night with high beams on you must dim them within 500 feet of an oncoming vehicle.
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Explain the difference between a fuse and a circuit breaker. If you were designing a circuit for a reading lamp, would you inclu
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The difference between a fuse and a circuit breaker is that a fuse is a one time circuit element while a circuit breaker is a multiple use device. If you were designing a circuit for a reading lamp, you should include a circuit breaker so you don't have to replace it every time.
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2 years ago
on the surface of theearth ,the weight of a boy is 400N but on a mountainpeak his weight is 360N,Calculatethe value of ''g' on t
andreyandreev [35.5K]

The value of g at sea level is 9.81 ms^-2.

The boy's mass is constant wherever he is in the universe but his weight will depend on the strength gravity where he is.

By proportion its value on the mountain peak  is (360 /400) * 9.81

= 0.9 * 9.81 = 8.83  ms^-2  to nearest hundredth,  (answer).

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3 years ago
I NEED HELP ASAP!!!
Savatey [412]
I think option C is correct..hope it helps
3 0
2 years ago
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The brakes on a bicycle apply 95 N of force to the wheels. When the
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Answer:

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Explanation:

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6 0
3 years ago
On a hot summer day, 3.50 ✕ 106 J of heat transfer into a parked car takes place, increasing its temperature from 36.5°C to 44.4
anygoal [31]

Answer:

a) \Delta s=443037.9747\ J.K^{-1}

b) \Delta s=31868131.8681\ J.K^{-1}

Explanation:

a)

Given:

amount of heat transfer occurred,dQ=3.5\times 10^6\ J

initial temperature of car, T_i=36.5+273=309.5\ K

final temperature of car, T_f=44.4+273=317.4\ K

We know that the change in entropy is given by:

\Delta s=\frac{dQ}{T_f-T_i}

\Delta s=\frac{3.5\times 10^6}{(44.4-36.5)} (heat is transferred into the system of car)

\Delta s=443037.9747\ J.K^{-1}

b)

amount of heat transfer form the system of house, dQ=5.8\times 10^8\ J

initial temperature of house, T_i=23.5+273=296.5\ K

final temperature of house, T_f=5.3+273=278.3\ K

\Delta s=\frac{dQ}{T_f-T_i}

\Delta s=\frac{5.8\times 10^8}{278.3-296.5}

\Delta s=31868131.8681\ J.K^{-1}

6 0
3 years ago
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