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Answer:
% yield = 73.48 %
Explanation:
The fermentation reaction is:
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
The percent yield of C₂H₅OH is given by:
<em>where : is the obtained mass of C₂H₅OH = 67.7g and
: is the theoretical mass of C₂H₅OH. </em>
The theoretical mass of C₂H₅OH is calculated knowing that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH:
<em>where M: is the molar mass of C₂H₅OH = 46.068 g/mol</em>
Hence, the percent yield of C₂H₅OH is:
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