Answer:
V₁ = 96.2 mL
Explanation:
Given data:
Initial volume of NH₄OH required = ?
Initial molarity = 15.6 M
Final molarity = 3.00 M
Final volume = 500.0 mL
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = Initial molarity
V₁ = Initial volume of NH₄OH
M₂ =Final molarity
V₂ = Final volume
Now we will put the values.
15.6 M ×V₁ = 3.00 M×500.0 mL
15.6 M ×V₁ = 1500 M.mL
V₁ = 1500 M.mL /15.6 M
V₁ = 96.2 mL
Answer:- Oxidation number of Cl does not change as it is -1 on both sides.
Explanations:- oxidation number of Mg on reactant side is 0 as it is in its elemental form(not combined with another element).
Oxidation number of hydrogen in its compounds is +1, so if H is +1 in HCl the oxidation number of Cl is -1 as the sum has to be zero.
On product side, Mg oxidation number is +2 as the oxidation number of alkaline earth metals in their compounds is +2.
Two Cl are present in magnesium chloride, so if Mg is +2 then Cl is -1.
Oxidation number of H on product side is 0 as it is present in its elemental for,
,
So, it is only chlorine(Cl) whose oxidation number does not change for the given equation.
To be honest, I can’t really see the question. So please next time just type it out lol
The ice sculpture would take longer to melt than the ice cube