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Citrus2011 [14]
3 years ago
9

A car hits a tree and doesn’t stop, but keeps going until severely damaged. This is because of _____.

Physics
2 answers:
ioda3 years ago
8 0

Answer:inertia

Explanation:

larisa86 [58]3 years ago
5 0
Inertia no explanation
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A current 2a flows in a circuit fir 2 minutes. Calculate the charge generated in a circuit​
nirvana33 [79]

Answer:

the charge generated in the circuit​ is 240 C.

Explanation:

Given;

current flowing in the circuit, I = 2A

time of current flow, t = 2 minutes = 2 x 60s = 120 s

The current flowing through a given circuit is defined as the quantity of charge flowing through the circuit in a given time.

I = \frac{Q}{t} \\\\Q = I t

where;

Q is the charge flowing in the circuit

Q = 2 x 120

Q = 240 C

Therefore, the charge generated in the circuit​ is 240 C.

3 0
4 years ago
What type of circuit is seen in this picture?<br><br> -Open<br> -Parallel<br> -Series<br> -AC
MA_775_DIABLO [31]

it's a. open circuit

3 0
3 years ago
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The standard unit for measuring volume is the _____.
Grace [21]
The answer that would best complete the given sentence above is cubic meter. The standard unit for measuring volume is the cubic meter (m^3). Volume is the quantity or the measurement of the amount of space that can be or is being occupied by matter. The metric unit for volume includes "liters" and "milliliters". 
6 0
3 years ago
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The relationship between energy (E), power (P), and time (t) is
NemiM [27]

Answer:

The avarage power of the body is 96.898 watts.

Explanation:

We must notice that given definition of power implies a constant consumption of energy, so that we should assume that energy consumption is constant. A Calorie is equal to 4186 joules. If we know that E = 2000\,Cal and t = 1\,day, the power of body, measured in watts, is:

P = \frac{(2000\,Cal)\cdot \left(4186\,\frac{J}{Cal} \right)}{(1\,day)\cdot \left(24\,\frac{h}{day} \right)\cdot \left(3600\,\frac{s}{h} \right)}

P = 96.898\,W

The avarage power of the body is 96.898 watts.

3 0
4 years ago
You pull on a spring whose spring constant is 22 N/m, and stretch it from its equilibrium length of 0.3 m to a length of 0.7 m.
Liono4ka [1.6K]

Answer:

W= 4.4 J

Explanation

Elastic potential energy theory

If we have a spring of constant K to which a force F that produces a Δx deformation is applied, we apply Hooke's law:

F=K*x  Formula (1): The force F applied to the spring is proportional to the deformation x of the spring.

As the force is variable to calculate the work we define an average force

F_{a} =\frac{F_{f}+F_{i}  }{2}  Formula (2)

Ff: final force

Fi: initial force

The work done on the spring is :

W = Fa*Δx

Fa : average force

Δx :  displacement

W = F_{a} (x_{f} -x_{i} )   :Formula (3)

x_{f} :  final deformation

x_{i}  :initial deformation

Problem development

We calculate Ff and Fi , applying formula (1) :

F_{f} = K*x_{f} =22\frac{N}{m} *0.7m =15.4N

F_{i} = K*x_{i} =22\frac{N}{m} *0.3m =6.6N

We calculate average force applying formula (2):

F_{a} =\frac{15.4N+6.2N}{2} = 11 N

We calculate the work done on the spring  applying formula (3) :         :

W= 11N*(0.7m-0.3m) = 11N*0.4m=4.4 N*m = 4.4 Joule = 4.4 J

Work done in stages

Work is the change of elastic potential energy (ΔEp)

W=ΔEp

ΔEp= Epf-Epi

Epf= final potential energy

Epi=initial potential energy

E_{pf} =\frac{1}{2} *k*x_{f}^{2}

E_{pi} =\frac{1}{2} *k*x_{i}^{2}

E_{pf} =\frac{1}{2} *22*0.7^{2} = 5.39 J

E_{pf} =\frac{1}{2} *22*0.3^{2} = 0.99 J

W=ΔEp=  5.39 J-0.99 J = 4.4J

:

4 0
3 years ago
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