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3 years ago

10

Transform boundaries occur where two plates – a slide past each other. b slide apart from each other. c slide towards each other

. d do not move.

1 answer:

iogann1982 [59]3 years ago

5 0

The answer is A slide past eatchother

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Diamond and graphite are two crystalline forms of carbon. In which form are the bonds between the C atoms arranged at tetrahedra

Fynjy0 [20]

Answer:

The answer is letter A. Diamond

Explanation:

The diamond is a crystalline form of carbon, with a cubic structure, of the sp³ type, that is, each carbon atom of the structure is linked to four other carbon atoms, forming a tetrahedral geometry.

3 0

3 years ago

⚠️NO LINKS⚠️(it will get reported)

brilliants [131]

Answer:

I'm thinking cooper but not sure

6 0

3 years ago

I need this answer quick please show work

Ainat [17]

Answer:

The answer to your question is 25.2 g of acetic acid.

Explanation:

Data

[Acetic acid] = 0.839 M

Volume = 0.5 L

Molecular weight = 60.05 g/mol

Process

1.- Calculate the number of moles of acetic acid

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = (0.839)(0.5)

-Result

moles = 0.4195

2.- Calculate the mass of acetic acid using proportions and cross multiplications

60.05 g ----------------------- 1 mol

x ----------------------- 0.4195 moles

x = (0.4195 x 60.05) / 1

x = 25.19 g

3.- Conclusion

25.2 g are needed to prepare 0.500 L of Acetic acid 0.839M

4 0

3 years ago

Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

3 years ago

Why do lows appear where there are more clouds and Highs appear where it is clear? (EXPLAIN)

7nadin3 [17]

If you mean temperature wise then it’s due to the clouds absorbing most of the sunlight, less clouds let’s more light through

4 0

2 years ago