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dolphi86 [110]
3 years ago
7

When a certain nuclide undergoes alpha emission, astatine-217 is produced. What is the identity of the nuclide that underwent de

cay?
a. actinium-219
b. francium-217
c. francium-221
d. astatine-221
e. actinium-221
Please explain the answer
Chemistry
1 answer:
Olin [163]3 years ago
8 0

Answer:

C: francium-221

Explanation:

First of all to get a broader perspective, every isotope of francium usually undergoes decay to form astatine, radium, or radon.

Now, Francium-223 and francium-221 are it's only isotopes that occur in nature.

However, francium-221 is the one that undergoes alpha decay to produce astatine-217.

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Simora [160]

If copper is heated with iron oxide there is no obvious reaction because

copper is less reactive than iron.

On a reactivity chart, copper is far below iron. This makes it impossible for a replacement reaction to occur, so the equation doesn't change.

I hope I helped!

5 0
3 years ago
Read 2 more answers
When aqueous solutions of manganese(II) iodide and sodium phosphate are combined, solid manganese(II) phosphate and a solution o
Feliz [49]

Answer:

The net ionic equation for the given reaction :

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

Explanation:

3MnI_2(aq)+2Na_3PO_4_2(aq)\rightarrow Mn_3(PO_4)_2(s)+6NaI(aq)...[1]

MnI_2(aq)\rightarrow Mn^{2+}(aq)+2I^-(aq)..[2]

Na_3PO_4(aq)\rightarrow 3Na^{+}(aq)+PO_4^{3-}(aq)...[3]

NaI(aq)\rightarrow Na^+(aq)+I^-(aq)

Replacing MnI_2(aq) , NaI and Na_3PO_4(aq) in [1] by usig [2] [3] and [4]

3Mn^{2+}(aq)+6I^-(aq)+6Na^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)+6Na^+(aq)+6I^-(aq)

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

8 0
3 years ago
The heating element of a hair dryer dissipates 1500 w when connected to a 180 v outlet. part a what is its resistance?
Sophie [7]

The resistance of the heating element is 21.61 Ω

Given

The power dissipated = 1500 W

Voltage = 180 V

We know that

Power = Voltage * Current

⇒ Power / Voltage = Current

⇒ 1500 W/180 V = Current

⇒ 8.33 A = Current

In order to calculate the resistance of the heating element. We Have to apply the formula

Power = (Current)^2 * Resistance

⇒ Resistance = Power / (Current)^2

⇒ Resistance = 1500 W/ (8.33) ^2

⇒ Resistance = 21.61 Ω

Hence the resistance of the heating element is 21.61 Ω

Learn more about resistance here: -

“ brainly.com/question/17330679  “

#SPJ4

5 0
2 years ago
How many moles of aluminum are equivalent to 4.816x10^24 atoms? 12.5 8 1.25 0.8
kotegsom [21]

Answer:

8

Explanation:

1 mole = 6.02 × 10²³ atoms

? moles = 4.816 × 10²⁴ atoms.

? Moles = 4.816 × 10²⁴ ÷ 6.02 × 10²³

? Moles = 8 moles

8 moles of aluminum = 4.816 × 10²⁴

4 0
3 years ago
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The antibiotic prontosil, developed by bayer pharmaceuticals in 1932, was used in saving the life of president roosevelt's son f
Alja [10]

Prontosil is a compound produced by the coupled reaction of an aryldiazonium ion and an aromatic compound.

<h3>What are diazonium compounds?</h3>

These are organic compounds in which there are ionic interactions between the azo group (-N₂⁺) and an anion X⁻.

The general structure is RN₂⁺X⁻.

  • R is the lateral chain that might be an aromatic ring, among other options.
  • N₂⁺ is the azo group
  • X⁻ is the anion

The azo group characterizes as being unstable and reactive. This property is because one of the N atoms has a positive charge.

-N⁺≡ N

<h3>What is the coupling reaction of aryldiazonium compounds?</h3>

Aryldiazonium salt reactions can occur in two ways,

  • Substitution reactions
  • Coupling reactions

Coupling reactions are the aromatic electrophilic substitution, where the aryldiazonium ion acts as an electrophile for an activated aromatic compound to attack it.

The coupling reaction occurs at the azo group level.

In the exposed example,

  • the benzene ring with sulfur bonded to oxygen atoms is the coupling component
  • the benzene ring with NH₂ and the azo group is the diazonium ion

In the attached files you will find the drawings.

You can learn more about diazonium compounds at

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