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4 years ago

Jim borrows $14,000 for a period of 4 years at 6 % simple interest. Determine the interest due on the loan. [4 marks

Mathematics

1 answer:

tino4ka555 [31]4 years ago

7 0

Answer: $ 3,360

Step-by-step explanation:

Given : The principal amount borrowed for loan : $P=\ \$14,000$

Time period : $t=4$

Rate of interest : $r=6\%=0.06$

The formula to calculate the simple interest is given by :-

$S.I.=P\times r\times t\\\\\Rightatrrow\ S.I.=14000\times4\times0.06\\\\\Rightatrrow\ S.I.=3360$

Hence, the interest due on the loan = $ 3,360

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almond37 [142]

Answer:

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Step-by-step explanation:

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9.7514 x 90 = X

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3 years ago

Write the quadratic equation in standard form:<br> 7x + 8 + 2x2<br> 2x + 1 + x2

JulsSmile [24]

Answer:

$3x^2 + 9x +9$

Step-by-step explanation:

Given

$(7x + 8 + 2x^2) + (2x + 1 + x^2)$

Required

The result in standard form

We have:

$(7x + 8 + 2x^2) + (2x + 1 + x^2)$

Remove brackets

$7x + 8 + 2x^2 + 2x + 1 + x^2$

Collect like terms

$7x+ 2x + 8 + 1 + 2x^2+ x^2$

$9x + 9+ 3x^2$

The standard form of a quadratic equation is:

$ax^2 + bx + c$

So, we have:

$9x + 9+ 3x^2$

$3x^2 + 9x +9$

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3 years ago

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masya89 [10]

Answer:

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Step-by-step explanation:

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3 years ago

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Zinaida [17]

Answer:

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Step-by-step explanation:

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Andrew [12]

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Step-by-step explanation:

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3 years ago

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