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This problem is describing the state two gases have when separated and together as shown on the attached picture. First of all, diagram 1 shows how they are separated in two containers with apparently equal volumes, whereas diagram 2 shows the removal of the barrier so that they get mixed together.
In this case, we can analyze that each gas has its own pressure and due to the removal of the barrier, both pressure and volume undergo a change. Thus, we can infer that the final volume is doubled with respected to the initial one for each gas, causing the pressure of each gas to be halved and the total pressure the half of the added ones, in agreement to the Boyle's law (inversely proportional relationship between pressure and temperature).
Therefore, the correct choice is:
C. The partial pressure of each gas in the mixture is half its initial pressure; the final total pressure is half the sum of the initial pressures of the two gases.
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277.79 atm is the calculated gas pressure.
The ideal gas is a fictitious concept used to study how real gases behave by comparing them to their deviations. The pressure-temperature rules are followed by an ideal gas.
177 atm is the initial pressure. The starting temperature is 298 K (25 °C = 25 + 273 °C).
195°C = 195+273
= 468K is the final temperature.
The pressure temperature relation illustrated below can be used to get the final pressure.
P1/T1 = P2/T1
= P1T2/T1
= 177 atm 468 K /298 K
= 277.97 atm
The final pressure is therefore 277.97 atm.
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