Answer:
The correct statement is option c, that is, particles discharged in the air by volcanoes fall to the ground and enrich the soil.
Explanation:
The eruptions of volcanoes lead to the dispersion of ash over the broader regions surrounding the site of eruption. On the basis of the chemistry of the magma, the ash will be comprising different concentrations of soil nutrients. While the major elements found in the magma are oxygen and silica, the eruptions also lead to the discharging of carbon dioxide, water, hydrogen sulfide, sulfur dioxide, and hydrogen chloride.
In supplementation, the eruptions also discharge bits of rocks like pyroxene, potolivine, amphibole, feldspar that are in turn enriched with magnesium, iron, and potassium. As an outcome, the areas which comprise huge deposits of the volcanic soil are quite fertile.
A biomolecule with a hydroxyl (--oh) functional group is
given the polar chemical property since organic molecules with an OH group are
polar.
A part of a larger molecule is made up by a functional
group. The hydroxyl group (-OH) that characterizes alcohols, an oxygen with a
hydrogen attached, is an example of it. This group can be found on any number
of different molecules.
Functional groups have characteristic chemistries, just
as elements have unique properties., although perhaps not identically,
to an -OH on another molecule. Although perhaps not
identically to an -OH on another molecule, an -OH group on one molecule will tend to react similarly.
Answer:
0.4033 M is the concentration of the sodium hydroxide solution.
Explanation:
Mass of potassium hydrogen phthalate = 2.023 g
Molar mass of potassium hydrogen phthalate = 204.22 g/mol
Moles of potassium hydrogen phthalate :
= 
According to reaction, 1 mole of potassium hydrogen phthalate reacts with 1mole of NaOH. Then 0.009906 moles of potassium hydrogen phthalate will recat with:
of NaOH
Moles of NaOH = 0.009906 mol
Volume of NaOH solution = 24.56 mL = 0.02456 L
![[NaOH]=\frac{0.009906 mol}{0.02456 L}=0.4033 M](https://tex.z-dn.net/?f=%5BNaOH%5D%3D%5Cfrac%7B0.009906%20mol%7D%7B0.02456%20L%7D%3D0.4033%20M)
0.4033 M is the concentration of the sodium hydroxide solution.
We are given with the percentage composition of oxygen in an oxide from phosphorus and oxygen equal to 43.6 percent. that is the phosphorus is equal to 56.4 percent. we divide each with the molar mass and divide each with the smaller quantity. P then is equal to 1 and O is equal to 1.5. In this case, the empirical formula is P2O3.
