The first integer (x) is equal to the consecutive even integers, x+2, x+4.
x = (x+2) + (x+4)
x = 2x + 6
x - 6 = 2x
x = -6 (First integer)
+2
-4 (Second integer)
+4
-2 (Third integer)
Integers: -6, -4, -2
Equation: x = (x+2) + (x+4)
Answer:
2 solutions:
x=5 and y=7
x=-1 and y=-5
Step-by-step explanation:
y=2x-3
y=x^2-2x-8
y=y so:
2x-3=x^2-2x-8
simplifying to:
x^2-4x-5=0
factoring to:
(x-5)(x+1)=0
x=5 or x=-1
if x=5 then y=2(5)-3=7
if x=-1 then y=2(-1)-3=-5
Answer:

Step-by-step explanation:
Required
Translate the statements to algebraic expression
Represent the power with x;
So, the left hand side is
<em>Power of 10: </em>
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<em>Times n: </em>
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The right hand side is:
<em>0.1515 * power of 10: </em>
<em />
Equate the right hand side to the left:


Hence;
<em>The required expression is </em>
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Answer:
Answer with explanation and steps are in the following attachment.
Step-by-step explanation:
Answer:
The second glue stick
Step-by-step explanation: