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olga_2 [115]
3 years ago
8

How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

Chemistry
2 answers:
puteri [66]3 years ago
6 0
5.4 M = moles of solute / 1.50 L 

<span>Multiply both sides by 1.50 L to isolate moles of solute on the right. </span>

<span>8.1 mol = moles of solute </span>


Cerrena [4.2K]3 years ago
6 0

8.1 mol KCI

This would be the answer.

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\huge\mathfrak\red {Answer:}

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