How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?
2 answers:
5.4 M = moles of solute / 1.50 L
<span>Multiply both sides by 1.50 L to isolate moles of solute on the right. </span>
<span>8.1 mol = moles of solute </span>
8.1 mol KCI
This would be the answer.
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Explanation:
I got it for you no worries
Answer: Convert to grams
Explanation:
Answer:
0.3758moles
Explanation:
moles of kcl = mass of kcl/ molar mass of kcl = 28/74.5 = 0.3758moles
It would be potassium chloride or kcl
