How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

2 answers:

6 0

5.4 M = moles of solute / 1.50 L

<span>Multiply both sides by 1.50 L to isolate moles of solute on the right. </span>

<span>8.1 mol = moles of solute </span>

Cerrena [4.2K]2 years ago

6 0

8.1 mol KCI

This would be the answer.

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