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Murrr4er [49]
3 years ago
6

Determine the average rate of decomposition of h3po4 between 10.0 and 40.0 s. express your answer with the appropriate units.

Chemistry
1 answer:
nirvana33 [79]3 years ago
8 0
Assume that we have this reaction 2H3PO4⇒ P2O5 + 3H2O
and when the rate of reaction is the speed at which the reactants can be changed and are converted into products So, according to our balanced reaction:

The rate of reaction = rate of formation of P2O5 
and the rate of this reaction also = 0.5 rates of decomposition of H3PO4 
∴ the rate of decomposition of H3PO4 = 2 rates of formation of P2O5
So when the rate of formation P2O5 = 2 x 10^-4 M/s 
So the rate of decomposition of H3PO4 = 2 x 2 x 10^-4
                                                                    = 4 x 10^-4 M/s


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Answer:

Solid

Explanation:

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3 years ago
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I will give brainliest!! How long is the pencil? Make sure to use the appropriate amount of significant figures.
8090 [49]

Answer: Option (c) is the correct answer.

Explanation:

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5 0
3 years ago
Nitrogen gas reacts with hydrogen gas to produce ammonia. How many liters of hydrogen gas at 95kPa and 15∘C are required to prod
viktelen [127]

Answer:

222.30 L

Explanation:

We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:

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= 14 + 3

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Mole = mass /molar mass

Mole of NH₃ = 100 / 17

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Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:

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From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, Xmol of H₂ is required to p 5.88 moles of NH₃ i.e

Xmol of H₂ = (3 × 5.88)/2

Xmol of H₂ = 8.82 moles

Finally, we shall determine the volume (in litre) of Hydrogen needed to produce 100 g (i.e 5.88 moles) of NH₃. This can be obtained as follow:

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Gas constant (R) = 8.314 KPa.L/Kmol

Volume (V) =?

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95 × V = 21118.89024

Divide both side by 95

V = 21118.89024 / 95

V = 222.30 L

Thus the volume of Hydrogen needed for the reaction is 222.30 L

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3 years ago
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Atomic or hybrid orbital on the central br atom makes up the sigma bond between this br and an outer f atom in bromine trifluoride, brf3 is sp2 hybridization

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