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3 years ago

Determine the average rate of decomposition of h3po4 between 10.0 and 40.0 s. express your answer with the appropriate units.

1 answer:

8 0

Assume that we have this reaction 2H3PO4⇒ P2O5 + 3H2O
and when the rate of reaction is the speed at which the reactants can be changed and are converted into products So, according to our balanced reaction:

The rate of reaction = rate of formation of P2O5
and the rate of this reaction also = 0.5 rates of decomposition of H3PO4
∴ the rate of decomposition of H3PO4 = 2 rates of formation of P2O5
So when the rate of formation P2O5 = 2 x 10^-4 M/s
So the rate of decomposition of H3PO4 = 2 x 2 x 10^-4
= 4 x 10^-4 M/s

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Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

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