3 years ago

The speedometer in your car reads 55 mi/h. This represents the what of the car

Physics

2 answers:

lozanna [386]3 years ago

5 0

Speed it's going an hour, how many miles it's going an hour?

frez [133]3 years ago

5 0

That's the car's instantaneous speed.

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Which two forms of electromagnetic energy are used to produce the

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3. ultraviolet and x rays

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3 years ago

At what height must a 6-kilogram object be placed to have 12 joules of

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0.2m

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12=6*9.8*h

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4 years ago

7 Calculate the weight of an apple of mass 100 grams

Leni [432]

Answer:

See the anwers below

Explanation:

To solve this problem we must understand that the weight of any $W = 0.1*10\\W = 1 [N]$ body is defined as the product of mass by gravitational acceleration. Gravitational acceleration depends on the place in space where a certain body is located.

$W = m*g\\$

where:

W = weight [N]

m = mass = 100 [g] = 0.1 [kg]

g = gravity acceleration [m/s²] or [N/kg]

Now for the Earth

$W =m*g\\W =0.1*10\\W = 1[N]$

For the Moon

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3 years ago

Driving 30.7 m/s in your car you see a dog up ahead and slam on your brakes. You stop just before hitting the dog after skidding

Nitella [24]

Answer: 2.74

Explanation:

We can solve this problem using the stopping distance formula:

$d=\frac{(V_{o})^{2}}{2 \mu g}$

Where:

$d=132.1 m$ is the distance traveled by the car before it stops

$V_{o}=30.7 m/s$ is the car's initial velocity

$\mu$ is the coefficient of friction between the road and the tires

$g=9.8 m/s^{2}$ is the acceleration due gravity

Isolating $\mu$ :

$\mu=\frac{2dg}{(V_{o})^{2}}$

Solving:

$\mu=\frac{2(132.1 m)(9.8 m/s^{2})}{(30.7 m/s)^{2}}$

$\mu=2.74$ This is the coefficient of friction

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3 years ago

Which component of the technological system is achieved when your camera takes a photograph?

IgorLugansk [536]

When this component is achieved when your camera takes a photograph that is a GOAL.

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3 years ago

Read 2 more answers