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Lemur [1.5K]
3 years ago
12

A rocket experiences a constant force even as the amount of fuel in its fuel tanks decreases. what happens to the acceleration o

f the rocket as it runs out of fuel?
Physics
2 answers:
Phantasy [73]3 years ago
8 0
<span>A rocket experiences a constant force even as the amount of fuel in its fuel tanks decreases. The acceleration on the other hand would increase since mass and acceleration is inversely proportional. By virtue of the equation F=ma. Hope this answers the question.</span>
Sergio [31]3 years ago
5 0

Answer:

D. The acceleration increases because the mass decreases.

Explanation:

I took the quiz and its right :)

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which words are readable red word on white paper in red light or blue words on white paper in blue light​
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In which of these cases do we have enough information to say that the atom is electrically neutral?
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2 years ago
1) Construct a graph showing the relationship between and independent variable and a dependent variable. 2) Demonstrate potentia
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Show two data points from your simulation that demonstrate this behavior.
Anestetic [448]

Answer:

hello your question is incomplete attached below is the complete and the required circuit diagrams

answer :

Ai) <em>This proves that when the current across the resistor is doubled the value of the voltage across the resistor doubles as well</em>

B) It is better to take more measurements in the range 20mA < I < 40mA because of the amount of temperature reached by the bulb and the change in resistance is affected by the temperature

hence At 0 mA current, there won't be any noticeable change

Explanation:

Ai) The voltage across the resistor will double when you double the current through the resistor

Given that : V = I*R.  

lets assume : I = 2 amperes , R = 3 ohms

V = 2*3 = 6 v

secondly lets assume double the value of  (I)   i.e. I = 4 amperes

hence : V = 4*3 = 12 volts

<em>This proves that when the current across the resistor is doubled the value of the voltage across the resistor doubles as well</em>

Aii) Showing the two data points from simulation

I1                    V1            I2= 2I1         V2=2V1       V1/ I1 =V2/I2

0.9*10^3     9 * 10^3     1.8*10^3       18*10^3          10 ohms

1.6 * 10^3    16 * 10^3    3.2*10^3     32*10^3         10 ohms

B) It is better to take more measurements in the range 20mA < I < 40mA because of the amount of temperature reached by the bulb and the change in resistance is affected by the temperature

hence At 0 mA current, there won't be any noticeable change

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