All categories

3 years ago

A 2.0-kg mass swings at the end of a light string (length = 3.0 m). Its speed at the

Physics

1 answer:

Virty [35]3 years ago

5 0

Answer:

Kinetic Energy = 36 Joules

Explanation:

Given =

Mass = 2kg

Velocity = 6m/s

Solution =

Kinetic Energy = 1/2 × mv²

Kinetic Energy = 1/2 × 2 × 6 × 6

Kinetic Energy = 36 Joules

You might be interested in

A 0.001kg bullet is fired with a velocity of 800m/s into a soft wood of mass 1kg resting on a smooth surface. Find the final vel

V125BC [204]

The final velocity of the bullet+block is 0.799 m/s

Explanation:

We can solve this problem by applying the principle of conservation of momentum: in fact, the total momentum of the bullet-block system must be conserved before and after the collision.

Mathematically, we can write:

$mu+MU=(m+M)v$

where

m = 0.001 kg is the mass of the bullet

u = 800 m/s is the initial velocity of the bullet

M = 1 kg is the mass of the block

U = 0 is the initial velocity of the block (initially at rest)

v is the final combined velocity of the bullet and the block

Solving the equation for v, we find the final velocity:

$v=\frac{mu}{m+M}=\frac{(0.001)(800)}{0.001+1}=0.799 m/s$

Learn more about conservation of momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

4 0

3 years ago

You can find electric power lines under the ground by looking for magnetic fields at ground level. This is best explained by whi

luda_lava [24]

What was the answer?

8 0

3 years ago

What is the total amount of heat in a substance

Setler [38]

The specific heat capacity of a substance is the amount of energy needed to change the temperature of 1 kg of the substance by 1 degree Celsius.

8 0

4 years ago

A car of mass m accelerates from speed v_1 to speed v_2 while going up a slope that makes an angle theta with the horizontal. Th

Karo-lina-s [1.5K]

Answer:

Work done by external force is given as

$Work_{external} = mgLsin\theta + \mu mgLcos(\theta) + \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$

Explanation:

As per work energy Theorem we can say that work done by all force on the car is equal to change in kinetic energy of the car

so we will have

$Work_{external} + Work_{gravity} + Work_{friction} = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$

now we have

$W_{gravity} = -mg(Lsin\theta)$

$W_{friction} = -\mu mgcos(\theta) L$

so from above equation

$Work_{external} - mgLsin\theta - \mu mgLcos(\theta) = \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$

so from above equation work done by external force is given as

$Work_{external} = mgLsin\theta + \mu mgLcos(\theta) + \frac{1}{2}mv_2^2 - \frac{1}{2}mv_1^2$

8 0

3 years ago

The current atmospheres of the terrestrial planets were formed when the planets formed

Alexus [3.1K]

A secondary atmosphere is an atmosphere of a planet that did not form by accretion during the formation of the planet's star. A secondary atmosphere instead forms from internal volcanic activity, or by accumulation of material from comet impacts. It is characteristic of terrestrial planets, which includes the other terrestrial planets in the Solar System: Mercury, Venus, and Mars. Secondary atmospheres are relatively thin compared to primary atmospheres like Jupiter's. Further processing of a secondary atmosphere, for example by the processes of biological life, can produce a tertiary atmosphere, such as that of Earth.

6 0

3 years ago