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otez555 [7]
3 years ago
5

. Ana has two mixtures. Mixture 1: marble and salt. Mixture 2: Salt and pepper She predicts she can easily separate the ingredie

nts from mixture-1 by sorting out using her fingers. i) Do you think that Ana's prediction was right? Give reason for your answer
Chemistry
1 answer:
MariettaO [177]3 years ago
7 0

Answer:

No

Explanation:

No, Ana's prediction of sorting out : mixture 1 'marble salt' with by her fingers, ie handpicking is not right.

Marble & salt particles mixture can't be sorted by handpicking. They can be seperated by the method of sieving rather, as marble particles being bigger stay in the sieve & salt particles being smaller (finer) pass through it.

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How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the so
expeople1 [14]

Answer:

2.72 grams

Explanation:

Complete question is

You are asked to pre pare a pH = 4.00 buffer starting from 1.50 L of 0.0200 M solution of benzoic acid

(C6H5COOH)

and any amount you need of sodium benzoate

(C6H5COONa)

How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the sodium benzoate is added.

Solution

Given

pH of the buffer solution = 4

Concentration of C6H5COOH = 0.02 M

Volume of the buffer solution = 1.50 L

K_a value for benzoic acid is 6.3 * 10^ {-5}

Concentration of sodium benzoate

pH = - log Ka + log \frac{C6H5COONa}{C6H5COOH}

Substituting the given values we get

log \frac{C6H5COONa}{C6H5COOH}  = 4 + log (6.3 * 10^ {-5})\\log \frac{C6H5COONa}{C6H5COOH}  = -0.20\\\frac{C6H5COONa}{C6H5COOH} = 10^{-0.2}\\{C6H5COONa} = 10^{-0.2} * 0.02\\{C6H5COONa} =  0.63 * 0.02\\{C6H5COONa} =  0.0126 M

Number of moles in sodium benzoate

= 0.0126 * 1.5 \\= 0.0189 Mol

Mass of sodium benzoate

0.0189 mol * 144.147 \frac{g}{mol} \\= 2.72 g

3 0
3 years ago
For a reaction for which AH = +29.3 kJ/mol and AS = +106 J/mol•K, which of the following statements is true? A) The reaction is
umka2103 [35]

Answer: A) The reaction is spontaneous above 276 K.

Explanation:

According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy  

\Delta H = enthalpy change  = +29.3 kJ/mol =29300 J/mol

\Delta S = entropy change  = +106 J/molK

T = temperature in Kelvin

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

\Delta G=(+ve)-T(+ve)

\Delta G=(+ve)(-ve)

T\Delta S>\Delta H  for reaction to be spontaneous

T\times 106 J/molK>29300J/mol

T>276K

Thus the Reaction is spontaneous when temperature is above 276 K.

8 0
3 years ago
what is the balanced chemical equation when solid calcium oxide and carbon dioxide gas are formed by the decomposition of solid
Ilya [14]
CaO(s) + CO2(g) -> CaCO3(s)
8 0
3 years ago
3 H2SO4(aq) + 2 Al(s) → Al2(SO4)3(aq) + 3 H2(g) How many moles of Al2(SO4)3 are produced when 6.5 moles of aluminum are consumed
Lera25 [3.4K]

Answer:

520 moles were produced

7 0
3 years ago
GIVEN BRAINLIEST
Yuliya22 [10]

Answer:

Hello, Your answer is <em>B) Making observations</em>

<u><em>(Hope That Helps Your Answer)</em></u>

3 0
4 years ago
Read 2 more answers
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