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Sladkaya [172]
3 years ago
11

If b humans cannot see ultraviolet waves how can ultraviolet light be used to gather evidence of a crime?

Physics
1 answer:
Inga [223]3 years ago
6 0
I don’t know because it’s very difficult
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A client with hypertension who weighs 72.4 kg is receiving an infusion of nitroprusside (Nipride) 50 mg in D5W 250 ml at 75 ml/h
Mkey [24]

To solve this problem it is necessary to simply apply the concepts related to cross-multiply and proportion between units.

Let's start first by relating the amount of dose needed to be supplied per hour, in other words,

The infusion of 250ml should be supplied at a rate of 75ml / hour, so what amount x of mg hour should be supplied with 50Mg.

\frac{x}{75ml/hour} \rightarrow \frac{50mg}{250ml}

x \rightarrow \frac{50mg*75ml/hour}{250ml}

x \rightarrow \frac{3750mg}{250hour}

x \rightarrow 15\frac{mg}{hour}

Converting to mcg units we know that 1mg is equal to 1000mcg and that 1 hour contains 60 min, therefore

x \rightarrow 15\frac{mg}{hour}

x \rightarrow 15\frac{mg}{hour}(\frac{1000mcg}{1mg})(\frac{1hour}{60min})

x \rightarrow 250mcg/min

The dose should be distributed per kilogram of the patient so if the patient weighs 72.4kg,

Dose = \frac{250mcg/min}{72.4kg}

Dose = 3.5 \frac{mcg/min}{kg}

Therefore the client will receive 3.5mcg/kg/min.

8 0
3 years ago
Carbon is allowed to diffuse through a steel plate 11 mm thick. The concentrations of carbon at the two faces are 0.88 and 0.41
Serhud [2]

Answer:

The temperature is 2584.5 K

Explanation:

Given:

Activation energy Q = 80000 \frac{J}{mol}

Preexponential D= 6.2 \times 10^{-7} \frac{m^{2} }{s}

Diffusion flux J = 6.4 \times 10^{-10} \frac{kg}{m^{2} s}

Thickness of plate \Delta x =  11 \times 10^{-3} m

Concentration of carbon at two faces \Delta C = (0.88 - 0.41 ) = 0.47 \frac{kg}{m^{3} }

From the formula of temperature in terms of diffusion flux,

  T = (\frac{Q}{R} ) \frac{1}{\ln (\frac{D\Delta C}{J\Delta x} )}

Where R = 8.314 \frac{J}{mol.K} ( gas constant )

Put the values and find the temperature,

  T = (\frac{80000}{8.314} ) \frac{1}{\ln (\frac{6.2 \times 10^{-7} \times 0.47 }{6.4 \times 10^{-10}\times 11 \times 10^{-3} } )}

  T = 2584.5 K

Therefore, the temperature is 2584.5 K

8 0
3 years ago
A ball starts from rest and rolls down a hill at a constant acceleration of 5 m/s2. If it travels for 8 m how fast is it going i
makkiz [27]

Hi there!

We can use the following kinematic equation:

v_f^2 = v_i^2 + 2ad

vf = final velocity (? m/s)
vi = intial velocity (0 m/s)

a = acceleration (5 m/s²)

d = displacement (8 m)

Plug in the givens and solve.

v_f^2 = 0 + 2(5)(8)\\\\v_f = \sqrt{80} = \boxed{8.944 \frac{m}{s}}

5 0
2 years ago
Gymnastics has great benefits for you both your body and mind? True False
Alenkasestr [34]

Answer:

I think the answer is True

6 0
2 years ago
Read 2 more answers
A 3.00-kg object undergoes an acceleration given by a = (2.00 i + 5.00 j) m/s^2. Find (a) the resultant force acting on the obje
kobusy [5.1K]

Answer:

(a): The resultant force acting on the object are F= (5.99 i + 14.98 j).

(b): The magnitude of the resultant force are F= 16.4 N < 68.19º .

Explanation:

m= 3kg

a= 2 i + 5 j = 5 .38 < 68.19 º

F= m * a

F= 3* ( 5.38 < 68.19º )

F= 16.4 N < 68.19º

Fx= F * cos(68.19º)

Fx= 5.99

Fy= F* sin(68.19º)

Fy= 14.98

3 0
3 years ago
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