It depends where you are.
-- If you weigh 120 pounds on the Moon,
then your mass is 329.1 kilograms.
-- If you weigh 120 pounds on Mars,
then your mass is 143.8 kilograms.
-- If you weigh 120 pounds on the Earth,
then your mass is 54.4 kilograms.
Answer:
Impulse = 322.5[kg*m/s], the answer is D
Explanation:
This method it is based on the principle of momentum and the amount of movement; and used to solve problems involving strength, mass, speed and time.
If units of the SI are used, the magnitude of the impulse of a force is expressed in N * s. however, when remembering the definition of the newton.

Now replacing the values on the following equation that express the definition of impulse
![Impulse = Force * Time\\\\Impulse = 215 * 1.5 = 322.5 [kg*m/s]](https://tex.z-dn.net/?f=Impulse%20%3D%20Force%20%2A%20Time%5C%5C%5C%5CImpulse%20%3D%20215%20%2A%201.5%20%3D%20322.5%20%5Bkg%2Am%2Fs%5D)
Answer:

Explanation:
When unpolarized light passes through the first polarizer, the intensity of the light is reduced by a factor 1/2, so
(1)
where I_0 is the intensity of the initial unpolarized light, while I_1 is the intensity of the polarized light coming out from the first filter. Light that comes out from the first polarizer is also polarized, in the same direction as the axis of the first polarizer.
When the (now polarized) light hits the second polarizer, whose axis of polarization is rotated by an angle
with respect to the first one, the intensity of the light coming out is
(2)
If we combine (1) and (2) together,
(3)
We want the final intensity to be 1/10 the initial intensity, so

So we can rewrite (3) as

From which we find



Answer:
Moment of inertia of the solid sphere:
I
s
=
2
5
M
R
2
.
.
.
.
.
.
.
.
.
.
.
(
1
)
Is=25MR2...........(1)
Here, the mass of the sphere is
M
M