Answer:
2407 kJ/mol
Explanation:
Given:
Mass of water = 40.00 kg
= 1.065 °C
Net Heat transfer during heating:
Specific heat of water = 4.187 kJ/kg°C
Q = 178.3662 kJ
Heat gained by water is heat lost by the compound. Thus, heat lost = 178.3662 kJ
Also,
Mass = 4.000 g
Molar mass of 
The formula for the calculation of moles is shown below:
Thus,
<u>Standard heat of formation = 178.3662 kJ / 0.0741 mol=2407 kJ/mol (In correct significant digits)</u>
Answer:
The coefficient in a balanced chemical equation indicates the mole ratio of both reactants and products.
Explanation:
For example lets consider the reation between Hydrogen and Oxygen to form water:
2H2 + O2 ----------------------- 2H2O
In this reaction, the coefficients of the balanced reaction can be transformed to Mole ratio according to Avogadro's Law which states that at standard temperature and pressure, equal volume of gases contain the same number of moles.
So the mole ratio for the above equation is the ratio of the coefficient:
2moles : 1 mole : 2 moles
Answer:
B. and A.
Explanation:
May I have the Brainlliest award?
Answer:
The total pressure would be 8, 93 atm
Explanation:
We apply Dalton's laws, where for a gaseous mixture, the total pressure (Pt) is the sum of the partial pressures (Px) of the gases that make up the mixture.
Pt= Pxa + Pxb+ Pxc....
Pt=2, 20 atm+ 6, 70 atm+ 0,03 atm= 8, 93 atm
