Answer:
8.33 moles CO2 X. 25mol O2. 16mol CO2. = 13.0 moles
<span>he accelerates when he runs away from home plate. as he reaches each base, the player accelerates by changing direction. he accelerates again when slowing down after reaching home plate.</span>
Answer:
The freezing point of the solution is - 4.39 °C.
Explanation:
We can solve this problem using the relation:
<em>ΔTf = (Kf)(m),</em>
where, ΔTf is the depression in the freezing point.
Kf is the molal freezing point depression constant of water = -1.86 °C/m,
density of water = 1 g/mL.
<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>
m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.
<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>
<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>
<em>∴ The freezing point of the solution is - 4.39 °C.</em>
To the top. Common knowledge my dude. Heat always rises to the top.
Answer:
hes actually kinda hot tho
Explanation:
