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Grace [21]
3 years ago
7

Two newly discovered planets follow circular orbits around a star in a distant part of the galaxy. The orbital speeds of the pla

nets are determined to be 45.6 km/s and 55.1 km/s. The slower planet's orbital period is 8.68 years. (a) What is the mass of the star? (b) What is the orbital period of the faster planet, in years?
Physics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

6.19744\times 10^{31}\ kg

4.91 years

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of star

v = Oribital velocity of star

T = Oribital time period

R = Radius of orbit

M=\frac{4\pi^2R^3}{GT}

v=\frac{2\pi r}{T}\\\Rightarrow R=\frac{vT}{2\pi}

\\\Rightarrow M=\frac{4\pi^2\left(\frac{vT}{2\pi}\right)^3}{GT}\\\Rightarrow M=\frac{Tv^3}{2\pi G}

\\\Rightarrow M=\frac{8.68\times 365.25\times 24\times 3600\times 45600^3}{2\pi 6.67\times 10^{-11}}\\\Rightarrow M=6.19744\times 10^{31}\ kg

Mass of the star is 6.19744\times 10^{31}\ kg

M=\frac{T_1v_1^3}{2\pi G}=\frac{T_2v_2^3}{2\pi G}\\\Rightarrow M=T_2v_2^3

\\\Rightarrow T_2=T_1\left(\frac{v_1}{v_2}\right)^3\\\Rightarrow T_2=8.68\left(\frac{45.6}{55.1}\right)^3\\\Rightarrow T_2=4.91\ years

Orbital period of the faster planet is 4.91 years

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First , we need to find the magnitude of the Force on the proton. This is given by the relation :
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Putting the respective values of v, B ,θ in the above equation, we get:

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What is the mass of an object that requires a force of 182 N to accelerate at a rate of 13 m/s?
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Answer:

m=14kg

Explanation:

Hello.

In this case, since the force is defined in terms of the mass and acceleration by:

F=m*a

We can easily compute the mass by solving for it:

m=\frac{F}{a}

Whereas the force is 182 N (kg*m/s²) and the acceleration is 13 m/s², therefore, we obtain:

m=\frac{182kg\frac{m}{s^2} }{13\frac{m}{s^2}}\\\\m=14kg

Best regards.

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3 years ago
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