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kenny6666 [7]
2 years ago
14

Constructive interference of two coherent waves will occur if the path difference is:___.

Physics
1 answer:
Olegator [25]2 years ago
8 0

Constructive interference of two coherent waves will occur if the path difference is λ/2.

<h3>Constructive interference:</h3>

When two waves are in phase and their maxima add, a process known as constructive interference occurs where the combined amplitude of the two waves equals the sum of their individual amplitudes.

The resultant wave is created by adding the amplitudes of two waves that are in phase and traveling in the same direction. The waves in this instance are said to have experienced beneficial interference. The upward displacement of the medium is higher than the displacement of the two interfering pulses because upward displacement occurs when the waves experience constructive interference. When the phase difference between the waves is an even multiple of (180°), constructive interference happens.

Learn more about  constructive interference here:

brainly.com/question/17329186

#SPJ4

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3 years ago
Nelle missioni di Apollo sulla Luna,il modulo di comando orbitava a un altitudine di 110 km al di sopra della superficie lunare.
liberstina [14]

Answer:

The period of orbit = 7143.41 s = 119.1 min = 1.984 hours

Il periodo dell'orbita = 7143.41 s = 119.1 min = 1.984 hours

Explanation:

English Translation

In Apollo's missions to the moon, the command module orbited at an altitude of 110 km above the lunar surface. How long did the command module complete an orbit?

Solution

According to Kepler's laws, the square of the period of orbit is proportional to the cube of the radius of orbit.

T² ∝ r³

T² = kr³

where k = constant of proportionality. The constant of proportionality is then given as

k = (4π²/GM)

It's all obtained from equating the gravitational force on the command module by the moon and the circular motion of the command module

Let

G = Gravitational constant

M = mass of the moon

m = mass of the command module

r = radius of orbit

w = angular velocity of the command module

(GMm/r²) = mrw²

(GM/r²) = rw²

(GM/r³) = w²

But angular velocity is given as

w = (2π/T)

w² = (4π²/T²)

(GM/r³) = (4π²/T²)

We then obtain

T² = (4π²/GM)r³

T² = kr³

Mass of moon = M = (7.35 x 10²²) kg Gravitational constant = G = (6.67 x 10⁻¹¹) Nm²/kg²

radius of moon = (1.74 x 10⁶) m

Total radius of orbit = 110 km + (radius of the moon) = 110,000 + (1.74 x 10⁶)

= (1.85 × 10⁶) m

k = (4π²/GM) = (4π² ÷ [(6.67 x 10⁻¹¹) × (7.35 x 10²²)] = (8.059 × 10⁻¹²) kg/Nm²

T² = kr³

T² = (8.059 × 10⁻¹²) × (1.85 × 10⁶)³

T² = 51,028,321.74

T = √(51,028,321.74) = 7,143.41107175

T = 7143.41 s = 119.1 min = 1.984 hours

Hope this Helps!!!

5 0
3 years ago
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