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3 years ago

Can someone help me

Physics

1 answer:

Illusion [34]3 years ago

5 0

Thomas Edison is the answer im 100% sure of it.

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Define the focus of a concave lens

Sophie [7]

Answer:

Principal focus of concave lens - 

★ The point at which rays parallel to principal axis coming from infinity appear to converge after being refracted from concave lens is called the principal focus of concave lens.

________________________

• Additional information - 

★ Principal focus - A number of rays parallel to the principal axis after reflection from a concave mirror meet at a point on the principal axis or appear to come from a point after reflection from a convex mirror on the principal axis. This is called principal focus.

8 0

3 years ago

A quantity of 14.1 cm^3 of water at 8.4°C is placed in a freezer compartment and allowed to freeze to solid ice at -7.2°C. How m

serious [3.7K]

Answer:920.31 J

Explanation:

Given

Volume of water (V) $=14.1 cm^3$

mass(m) $=\rho \times V=1000\times 14.1\times 10^{-6}=14.1 gm$

Temperature $=8.4^{\circ} C$

Final Temperature $=-7.2 ^{\circ}C$

specific heat of water(c) $=4.184 J/g-^{\circ}C$

Therefore heat required to removed is

$Q=mc(\Delta T)$

$Q=14.1\times 4.184\times (8.4-(-7.2))$

$Q=920.31 J$

3 0

4 years ago

Define First Condition of Equilibrium ??

spayn [35]

Answer:

First Condition of Equilibrium is that it must be experiencing no acceleration or the external forces acting on the body should be zero.

7 0

3 years ago

Read 2 more answers

The following equation is an example of decay? 232/90 TH---4/2 HE +228/88 RA?

DaniilM [7]

Answer:

Alpha decay

Explanation:

Alpha decay is one of the three major types of decays, others being, beta decay and gamma decay.
When a radioactive isotope undergoes alpha decay it emits alpha particles. An alpha particle is equivalent to the nucleus of Helium atom.
Therefore, an atom undergoing decay, its atomic mass is decreased by 4 and its atomic number is decreased by 2.
Thus, since 232/90 Th, has undergone alpha decay its mass number is reduced by 4 to 228 and its atomic number by 2 to 88, and becomes 228/88 Ra.

5 0

3 years ago

The current through a heater is 12 A when it is plugged into a

jasenka [17]

Answer:

A. 10Ω

Explanation:

7 0

3 years ago