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zheka24 [161]
2 years ago
15

Based on the information you know about friction discuss with your group how you could experimentally determine the coefficient

of static friction between a rough block and your incline plane. How is it similar or different to the procedure of the experiment you performed today with the smart cart? Hint: Remember the relationship between the applied force and the coefficient of static friction.
Physics
1 answer:
Alona [7]2 years ago
5 0

Answer:

The experiment to determine the coefficient of static friction between a rough block and an incline plane is detailed in the explanation.

Explanation:

A simple experiment is as follows:

Take a weight in which its mass is known and hold it with a roller at the end of the inclined plane with a rope.

Place the weight on the plane inclined horizontally with the ground, forming a zero degree angle.

Gradually lift the weight so that the angle of incline begins to increase.

Observe that the weight will begin to slide. This angle will be the angle theta.

In this way, the coefficient of friction will be calculated as the tangent of the angle theta.

Take a different weight and repeat the procedure to get different values ​​of the coefficient of friction.

By averaging the coefficients of friction, a final value will be obtained.

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A team of dogs accelerates a 290kg dogsled from 0 to 6.0m/s in 3.0 s. Assume that the acceleration is constant.Part AWhat is the
Mademuasel [1]

Answer:

(a) a=2m/sec^2

(b) 5220 j

(c) 1740 watt

(d) 3446.66 watt

Explanation:

We have given mass m = 290 kg

Initial velocity u = 0 m/sec

Final velocity v = 6 m/sec

Time t = 3 sec

From first equation of motion

v = u+at

So a=\frac{v-u}{t}=\frac{6-0}{3}=2m/sec^2

(a) We know that force is given by

F = ma

So force will be F=290\times 2=580N

(b) From second equation of motion we know that

s=ut+\frac{1}{2}at^2=0\times 3+\frac{1}{2}\times 2\times 3^2=9m

We know that work done is given by

W = F s = 580×9 =5220 j

(c) Time is given as t = 3 sec

We know that power is given as

P=\frac{W}{t}=\frac{5220}{3}=1740Watt

(d) Time t = 1.5 sec

So P=\frac{W}{t}=\frac{5220}{1.5}=3466.66Watt

5 0
3 years ago
A certain superconducting magnet in the form of a solenoid of length 0.56 m can generate a magnetic field of 6.5 T in its core w
Gnom [1K]

Answer:

The value  is N =36203 \  turns

Explanation:

From the question we are told that

   The length of the solenoid is  l = 0.56 \  m

   The magnetic field is B  =  6.5 \ T

    The current is I = 80 \ A

     The desired temperature is  T = 4.2 \ K

Generally the magnetic field is mathematically represented as

       B  = \frac{\mu_o * N * I }{L }

=>     N = \frac{B  * L }{\mu_o * I }

Here  \mu_o is the permeability of free space with value  

      \mu_o =  4\pi * 10^{-7} N/A^2

So

     N = \frac{6.5  * 0.56 }{ 4\pi * 10^{-7} *  80  }

=>   N =36203 \  turns

6 0
2 years ago
Is it possible for a population with a high birth rate to decrease in size.
matrenka [14]
Sure, if the mortality (death) rate is even higher than the birth rate.
7 0
3 years ago
A person covers a distance of 320 miles in a travel time of 8 hours. What is the speed for this trip?
goldfiish [28.3K]
Take 320 and divide by 8
320/8 = 40 mi/hr or A
8 0
3 years ago
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HELP ASAP! GIVING BRAINLIEST!!!<br><br> I need the answers to 1,2,3!!
artcher [175]

1) 72/4 = 18 years

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Let me know if you have any questions.

7 0
3 years ago
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