Answer:
= 38.89 m/s
Explanation:
speed of first car (u) = 80 km/h = 22.22 m/s
time (t) = 30 s
distance (d) = 500 m
find the speed of second car (v)
let the speed of the second car be represented as 'v'
We can get the speed of the second car from the formula net speed = distance between cars / time interval
where
- distance between cars = 500 m
- time interval = 30 s
- net speed = v-22.22 (since both cars move in the same direction)
- substituting the above into the formula we have
v-22.22 = 500 / 30
v = 500/30 + 22.22
v = 38.89 m/s
In this item if we let x be the number of doubling period, that is number of days divided by 3, and y be the height of the bamboo shoot, in the equation
y = ab^x
The value of a is 5 because that is the original height of the shoot and b is 2 because we are talking about the doubling rate. The equation is therefore,
y = 5(2^x)
Answer: F
Explanation: The boy is controlling the bowling ball therefore he can use greater force
Please look up the answer on Brainly before answering again.
For car A: y=20x-200 A moves 20 meters every second x, and starts 200m behind BFor Car B: y= 15x B moves 15 meters every second and starts at basisSet two equations equal to each other to find time x where they meet:20x - 200 = 15x200 = 5x x= 40A moves 20 meters every second:20x40=800m
Answer:
See below.
Explanation:
The difference between these two is that a wave is a disturbance of some quantity in space or intermediate while a particle has a definite mass concentrated on a small area.
