Taking motion towards East as +ve ....
(0.65kg x 3.0m/s) + (0.65kg x - 2.0m/s) = 0.65 kg.m/s
(0.65 x v?) + (0.65 x - 1.50) = 0.65(v - 1.50)
By conservation .. before = after
0.65 = 0.65(v - 1.50)
1 = (v - 1.5) .. .. ►v = (+) 2.50 m/s (East)
The magnitude of the charge is 12 N in the opposite direction of the field.
<h3>What is Electric field?</h3>
The term electric field refers to the region in space where the effect of a charge is felt. In this case, we are told that the magnitude of the charge is –0.06 C.
Hence;
E = F/q
F = Eq
F = –0.06 C * 200 N/C
F = 12 N
Hence, the magnitude of the charge is 12 N in the opposite direction of the field.
Learn more about electric field: brainly.com/question/15800304
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