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4 years ago

What does the DHCP server configures for each host?

Engineering

1 answer:

lidiya [134]4 years ago

8 0

Answer: IP address

Explanation:

DHCP server automatically assigns an IP address and other information to each host on the network so they can communicate efficiently with other endpoints

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Petroleum engineers work almost exclusively with dry materials.<br><br><br> False<br> True

spin [16.1K]

True since they’re engineers they don’t mess with the actual petroleum

7 0

3 years ago

In a river reach, the rate of inflow at any time is 350 cfs and the rate of outflow is 285 cfs. After 90 min, the inflow and out

Semenov [28]

Answer:

change in storage = -310,500 ft^3

intital storage= 3.67 acre ft

Explanation:

Given data:

Rate of inflow = 350 cfs

Rate of outflow = 285 cfs

After 90 min, rate of inflow = 250 cfs

Rate of outflow = 200 cfs

final storage = 10.8 acre-ft

calculating the average inflow and outflow

average inflow $= \frac{(350+250)}{2} = 300 cfs$

average outlow $= \frac{(285+200)}{2} = 242.5 cfs$

total amount of water drain during the period of one hour

= (average outflow - average inflow) *60*90

= (242.5 - 300)*60*90 = -310,500

change in storage is calculate as

= -310,500 ft^3

in cubic meter

= -310500/35.315 = 8792.30 cm^3

in acre-ft

= -310,500/43560 = 7.13 acre ft

initial storage = 10.8 - 7.13 = 3.67 acre ft

3 0

3 years ago

A vehicle of 1 200 kg is moving at a speed of 40 km/h on an incline of 1 in 50. The total constant rolling and wind resistance i

Readme [11.4K]

Answer:11.602 KW

Explanation:

mass of vehicle $\left ( m\right )=1200 kg$

speed=40Km/h

Resistance=600 N

$\eta =80%$

Gear ratio $\left ( G\right )=4:1$

$D_{effective}=500mm$

Net force to overcome by engine is

F=Resistance + sin component of weight

F=600+ $mgsin\theta$

Where $tan\theta =[tex]\frac{1}{50}$

$\theta =1.1457^{\circ}$

$F=600+1200\times 9.81\times sin\left ( 1.1457\right )$

F=600+235.38=835.38 N

power= $F.v=835.38\frac{100}{9}$

Engine Power= $\frac{835.\frac{100}{9}}{\eta }$ =11.602 KW

4 0

4 years ago

4. Calculate the square root of potato using the sqrt() function. Print out the value of potato again to verify that the value o

N76 [4]

Answer:

potato<-100

print(potato)

sqrt(potato)

potato<-potato*2

print(potato)

Explanation:

The complete question is as follows

Create a variable called potato whose value corresponds to the number of potatoes you’ve eaten in the last week. Or something equally ridiculous. Print out the value of potato.

Calculate the square root of potato using the sqrt() function. Print out the value of potato again to verify that the value of potato hasn’t changed.

Reassign the value of potato to potato * 2.

Print out the new value of potato to verify that it has changed

The question was answered using R programming language.

At line 1, I assumed that I ate 100 potatoes in the previous week.

So, potato = 100

At line 2, the value of potato is printed as 100.

At line 3, the square root of potato is calculated using sqrt function: Square for of 100 = 10

At line 4,the initial value of potato is doubled and stored in potato variable. 100 * 2 = 200

At line 5, the new value of potato is printed: 200.

8 0

4 years ago

대한민국의 주권은 국민에게 있고. 예비비의 지출은 차기국회의 승인을 얻어야 한다, 대통령은 국가의 안위에 관계되는 중대한 교전상태에 있어서 국가를 보위하기 위하여 긴급한 조치가 필요하고 국회의 집회가 불가능한 때에 한하여 법률의

mote1985 [20]

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3 years ago