Answer:
a ) 11.1 *10^3 m/s = 39.96 Km/h
b) T_{o2} =1.58*10^5 K
Explanation:
a)
= 11.1 km/s =11.1 *10^3 m/s = 39.96 Km/h
b)
M_O2 = 32.00 g/mol =32.0*10^{-3} kg/mol
gas constant R = 8.31 j/mol.K

So, 
multiply each side by M_{o2}, so we have

solving for temperature T_{o2}

In the question given,

T_{o2} =1.58*10^5 K
I think Option B, i’m sorry if that’s wrong.
Density(rho) = m/v
(1.3)/((3.2)(17.1)(3.8))
since density is given in kg/m^3 you should convert the blocks dimensions to meters
1.3/(0.032*0.038*0.171)
plugging in these numbers would give you the density
1.3/0.000208
6250
with sigfigs= 6300kg/m^3