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3 years ago

15

The apartment’s explosion, reportedly caused by a gas leak, produced a violent release of gas and heat. the heat increased the _

____ of the air in the room, which means an increase in the air's molecular kinetic energy.

1 answer:

Levart [38]3 years ago

4 0

<span>The apartment’s explosion, reportedly caused by a gas leak, produced a violent release of gas and heat. the heat increased the temperature of the air in the room, which means an increase in the air's molecular kinetic energy.

When heat leaves a system, that energy is transferred to its surroundings. Since the air is the surroundings, the heat is transferred to the air increasing the temperature. This causes an increase in the individual air molecules' energy.</span>

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The small piston of a hydraulic press has an area of 3.2 in2. If the applied force is 2.0 lb, what must the area of the large pi

BartSMP [9]

Given data:

The area of the hydraulic press is,

$A_1=3.2in^2$

The applied force is,

$F_1=2\text{ lb}$

The pressing force on the large piston is

$F_2=795\text{ lb}$

Given hydraulic press works on Pascal's law principle.

From the Pascal's law, the equation can be given as,

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

Here,

$A_2$

is the area of the larger piston.

Substituting the values in the above equation, we get:

$\begin{gathered} \frac{2\text{ lb}}{3.2in^2}=\frac{795\text{ lb}}{A_2} \\ A_2=1272in^2 \end{gathered}$

Thus, the area of the large piston is

$1272in^2$

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1 year ago

A projectile proton with a speed of 500 m/s collides elastically with a target proton initially at rest. The two protons then mo

makkiz [27]

Answer:

(a) The speed of the target proton after the collision is: $V_{2f} =433(m/s)$ , and (b) the speed of the projectile proton after the collision is: $v_{1f}=250(m/s)$ .

Explanation:

We need to apply at the system the conservation of the linear momentum on both directions x and y, and we get for the x axle: $m_{1} v_{1i} =m_{1} v_{1f}Cos\beta _{1} +m_{2} v_{2f}Cos\beta _{2}$ , and y axle: $0=m_{1} v_{1f}Sin\beta _{1}+m_{2} v_{2f}Sin\beta _{2}$ . Now replacing the value given as: $v_{1i}=500(m/s)$ , $\beta_{1}=+60^{o}$ for the projectile proton and according to the problem $\beta_{1}and\beta_{2}$ are perpendicular so $\beta_{2}=-30^{o}$ , and assuming that $m_{1}=m_{2}$ , we get for x axle: $500=v_{1f}Cos\beta _{1}+ v_{2f}Cos\beta _{2}$ and y axle: $0=v_{1f}Sin\beta _{1}+v_{2f}Sin\beta _{2}$ , then solving for $v_{2f}$ , we get: $v_{2f}=-v_{1f}\frac{Sin\beta_{1}}{Sin\beta_{2}}= \sqrt{3}v_{1f}$ and replacing at the first equation we get: $500=\frac{1}{2} v_{1f} +\frac{\sqrt{3}}{2} *\sqrt{3}*v_{1f}$ , now solving for $v_{1f}$ , we can find the speed of the projectile proton after the collision as: $v_{1f}=250(m/s)$ and $v_{2f}=\sqrt{3}*v_{1f}=433(m/s)$ , that is the speed of the target proton after the collision.

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3 years ago

The velocity of a passenger relative to a boat is -vpb. The velocity of the boat relative to the river it is moving on is vbr. T

RideAnS [48]

Answer:

vps = vbr + vrs - vpb

Explanation:

If the passenger were at rest, his speed relative to the shore will be identical to the boat's, as follows:
vps = vbr + vrs
As he is moving in a direction opposite to the boat's, his velocity relative to the shore must be less than if he were at rest, in the same quantity that he was moving opposite to the boat, as follows:
vps = vbr+ vrs -vpb

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2 years ago

Bacteria prefer a dry environment to a damp or moist environment. False True

mariarad [96]

Answer:

false

Explanation:

cause bacteria prefers moist and damp environment

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3 years ago

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satela [25.4K]

<em>Inertia</em> is the property of all matter by which it tends to remain in constant, uniform motion until it's acted on by an external force.

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3 years ago

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