antimony(III) sulfide is reacted with excess iron. if 175.6 grams of pure antimony is produced what mass of antimony sulfide was
1 answer:
Answer: -
The chemical formula of Antimony(III) sulfide = Sb₂S₃
Mass of Sb produced = 175.6 g
Molar mass of Sb = 121.76 g /mol
Number of moles of Sb = 175.6g / (121.76 g/mol)
= 1.44 mol
The balanced chemical equation for this reaction is
Sb₂S₃ + 3 Fe → 2 Sb + 3 FeS
From the chemical equation we see
2 mol of Sb is produced from 1 mol of Sb₂S₃
1.44 mol of Sb is produced from
= 0.72 mol of Sb₂S₃
Molar mass of Sb₂S₃ = 2 x 121.76 + 32.06 x 3
= 339.7 g / mol
Mass of Sb₂S₃ = 0.72 mol x 339.7 g/ mol
= 244.58 g
= 244.6 g rounded off to 4 significant figures.
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