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2 years ago

The attractive forces in a solid tend to be________ than in the liquid state

Chemistry

1 answer:

Anika [276]2 years ago

5 0

Answer: stronger

Explanation:

the attractive forces in a solid tend to be stronger_ than in the liquid state, for the liquid state it tends to be weaker

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Two spherical objects with a mass of 7.73 kg each are placed at a distance of 1.11 m apart. how many electrons need to leave eac

aliina [53]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Equate the gravitational force to the electrostatic force:

<span>KC²/D² = Gm²/D² → C = m√[G/K] = 7.6√[6.67E-11/9E9] = 6.54E-10 coulombs </span>

<span>Number of electrons N = 6.24E18*C = 4.083E9 electrons</span>

4 0

2 years ago

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

7 0

3 years ago

Can plants stop soil erosion

motikmotik

Answer:

yes. they can block the wind which causes top soil erosion and they also soak up some the water in the soil

4 0

3 years ago

Given the reaction:

STatiana [176]

answer:

as per the formula of given carbohydrate the answer is 15 moles

explanation:

1 mole carbohydrate contains 6 moles water
2.5 moles contain 6 X 2.5 = 15 moles

7 0

3 years ago

To answer this question, you may need access to the periodic table of elements.

OleMash [197]

Answer:

b.) Br and Br

Explanation:

A covalent bond occurs when electrons are shared between two atoms causing them to form a bond.

A "pure" covalent bond refers to a nonpolar covalent bond. In these bonds, the electrons are shared equally between two atoms as a result of the absence of an (or very small) electronegativity difference. The purest covalent bond would therefore be between two atoms of the same electronegativity. Two bromines (Br) have the same electronegativity, thus making it the purest covalent bond.

Polar covalent bonds occur when electrons are shared unequally between two atoms. There is a larger electronegativity difference between the two atoms, but not large enough to classify the bonds as ionic. In this case, a.) and c.) are polar covalent bonds and d.) is an ionic bond.

7 0

10 months ago

The attractive forces in a solid tend to be________ than in the liquid state​

The attractive forces in a solid tend to be________ than in the liquid state