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Andrew [12]
3 years ago
14

Complete and balance the precipitation reactions. Include physical states. Refer to the solubility rules as necessary. precipita

tion reaction: AgNO_{3}(aq) + NaCl(aq) -> AgNO3(aq)+NaCl(aq)⟶ precipitation reaction: K_{3}PO_{4}(aq) + MgCl_{2}(aq) -> K3PO4(aq)+MgCl2(aq)⟶
Chemistry
1 answer:
Tcecarenko [31]3 years ago
3 0

The balanced chemical reactions are:

AgNO{_3}(aq) \ + \ NaCl(aq) \rightarrow \ AgCl(s) \ + NaNO_{3}(aq)\\2K_{3}PO_{4}(aq) \ + 3MgCl_{2}(aq) \rightarrow \ 6KCl(aq) \ + Mg_{3}(PO_{4})_{2}(s)

Further Explanation:

The following reactions will undergo double displacement where the metal cations in each compound are exchanged and form new products.

For reaction 1, the compounds involved are nitrates and chlorides. To determine the states of the products, the solubility rules for nitrates and chlorides must be followed:

  • All nitrates are generally soluble.
  • Chlorides are generally soluble except AgCl, PbCl2, and Hg2Cl2.

Therefore, the products will have the following characteristics:

  • silver chloride (AgCl) is insoluble
  • sodium nitrate (NaNO3) is soluble

For reaction 2, the compounds involved are phosphates and chlorides. The solubility rules for phosphates and chlorides are as follows:

  • Phosphates are generally insoluble except for Group 1 phosphates.
  • Chlorides are generally soluble except for AgCl, PbCl2, and Hg2Cl2.

Hence, the products of the second reaction will have the following characteristics:

  • potassium chloride (KCl) is soluble
  • magnesium phosphate is insoluble

Insoluble substances are denoted by the symbols (s) in a chemical equation. The soluble substances are denoted as <em>(aq).</em>

Learn More

  1. Learn more about solubility brainly.com/question/1163248
  2. Learn more about solubility rules brainly.com/question/1447161
  3. Learn more about net ionic equations brainly.com/question/12980075

Keywords: solubility rules, precipitation reaction

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Explanation:

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3 years ago
Determine the number of bonding electrons and the number of nonbonding electrons in the structure of OF2. Enter the number of bo
kvasek [131]

Answer:

(4,20)

Explanation:

Oxygen di-fluoride or OF2 is a polar molecule, formed through the covalent bonding between one Oxygen and two Fluorine atoms.

Oxygen has atomic no. 8 and its electronic configuration is as below:

  • 1s^2, 2s^2, 2p^4

Oxygen has 4 electrons in the valence shell. It has the ability to share two electrons with other atoms through covalent bond and get stable.

The atomic number of Fluorine is 7, and its electronic configuration is as:

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So, Fluorine atom  has the capacity to accept 1 electron to form 1 covalent bond or in the formation of the F- ion.  

The structure of OF2 is a bent structure with O atom sandwiched by two fluorine atoms like F-O-F. So there are two electrons on oxygen atom that are taking part in the formation of covalent bond with each Fluorine atom (Please dot structure in figure).

Now we can easily calculate no of bonding and non-bonding electrons.

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Hope it helps! :)


3 0
3 years ago
Read 2 more answers
5000kg of ammonium nitrate per square kilometer of cornfield per year. how much nitric acid would be needed to make the fertiliz
Serggg [28]

NH_3+HNO_3-> NH_4NO_3

1 mole of nitric acid produce 1 mole of ammonium nitrate.

moles in 5000 kg of ammonium nitrate :

n=\dfrac{5000\times 1000}{80}\\\\n=62500\ moles ( molecular mass of ammonium nitrate is 80 gm/mol )

So, number of moles of nitric acid required are also 62500 moles.

Mass of 62500 moles of nitric acid :

mass = 62500\times 63 \\\\mass = 3937500\ gram\\\\mass = 393.75\ kg

Hence, this is the required solution.

5 0
3 years ago
A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-Q_1=Q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

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5 0
4 years ago
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OverLord2011 [107]

Answer:

So there is83.6g CO2 produced

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This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2

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So there is83.6g CO2 produced

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3 years ago
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