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Tpy6a [65]
4 years ago
9

Which of the following is not a simple machine?

Physics
2 answers:
erica [24]4 years ago
8 0

Answer:

C

Explanation:

A wheel and axle, a lever, and a screw are all simple machines.

A pair of scissors is not a simple machine.

Answer is C.

faltersainse [42]4 years ago
5 0

C. scissors are a TYPE of. it is not a simple machine

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Which of the following was not first proposed by Charles Darwin?
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C. Struggle for existence

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Have a great day

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Vector A with arrow lies in the xy plane. Both of its components will be negative if it points from the origin into which quadra
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C

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Generally  in the x and y plane thr negative y axis is made to face down opposite the positive y axis

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3 years ago
Which force acts between two surfaces to prevent or slow motion
vredina [299]
The answer is friction
4 0
3 years ago
An applied force of 20 N is used to accelerate an object to the right across a
vichka [17]

Answer:

F_{norm} = 100 N

F_{net}=10 N

\mu = 0.10

m = 10 kg

a=1.0 m/s^2

Explanation:

To determine the normal force, we just need to analyze the situation along the vertical direction.

The box along the vertical direction is in equilibrium, so the equation of the forces is

F_{norm} - F_{grav} = 0

which means that

F_{norm} = F_{grav} = 100 N

The net force can be determined by looking at the situation along the horizontal direction (since the net force in the vertical direction) is zero. Here we have:

- An applied force of 20 N forward, F_{app} = 20 N

- A frictional force of 10 N backward, F_{frict} = 10 N

So, the net force is

F_{net}=F_{app}-F_{frict}=20-10 = +10 N in the forward direction

The expression for the frictional force is

F_{frict} = \mu F_{norm}

where \mu is the coefficient of friction. Solving for \mu,

\mu = \frac{F_{frict}}{F_{norm}}=\frac{10}{100}=0.10

The force of gravity is given by

F_{grav}=mg

where m is the mass of the object and g=10 m/s^2. Solving for m, we find the mass of the object:

m=\frac{F_{grav}}{g}=\frac{100}{10}=10 kg

Finally, the acceleration can be found by using Newton's second law

F_{net} = ma

where a is the acceleration. Solving for a,

a=\frac{F_{net}}{m}=\frac{10}{10}=1.0 m/s^2

4 0
3 years ago
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