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Klio2033 [76]
3 years ago
13

Based on the article "Will the real atomic model please stand up?,” describe one major change that occurred in the development o

f the modern atomic model.
Chemistry
2 answers:
ololo11 [35]3 years ago
4 0

Sample Response: "The one major change that occurred was the placement and organization of the electron. Rutherford’s model identified that the electrons were at a distance from the nucleus, Bohr’s model identified that the electrons occurred at levels that related to their available energy, and the modern atomic model shows that electrons are located in a predicted area but cannot be identified in a specific point".

nydimaria [60]3 years ago
3 0
I don't know this article, but I do know some major changes: first, the change from the plum pudding model (no nucleus, just electrons) to the gold foil experiment, which had Rutherford shoot alpha particles at a sheet of gold only to find them rebounding, proving the existence of a positively charged mass, i.e a nucleus, in the atom. However, this changed again when Bohr realized that the negatively charged electrons should be attracted to the positively charged center, so that there must be something else inside the nucleus. 
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A 25.0 ml sample of water at 90 °c has a mass of 24.12 g. Calculate the density of water at this temperature.
ycow [4]

solution:

Density of water the density of water is greatest at about four degrees C (39.2° F or 277degrees Kelvin) which is a density of 1.000 kg per liter (62.4 pounds per cubic foot). Liquids expand slightly as their temperature is raised, but liquid water is denser than solid water (ice). That is why ice floats: it is less dense than liquid water. That is due to the crystal structure of ice. When water freezes, its volume increases about nine percent. 277 K. Density rho = mass m / Volume V. Water has a density of 1,000 kg/m3 = 1,000 g/L = 1.000 kg/dm3 = 1.000 kg/L = 1.000 g/cm3 = 1.000 g/mL at the temperature of 3.98 degrees Celsius. Temperature in degrees Celsius and the density of water: 1  

At 4 °C, its density is the greatest and is equal to 1000 kilograms per cubic meter (SI unit). At any other temperature, its density is less than 1000 kilograms per cubic meter. The answer "1.0" is wrong. Water is unique in that it is one of the only substances that actually expands and becomes less dense as the temperature increases. Water molecules (H 2 O) have a special shape and arrangement; this is why ice floats above the warmer water on a frozen lake. To convert grams/cm3 or grams/mL (1 cm 3 = 1 mL) into other units, use these conversions: 1 dry ounce = 28.349 grams 1 fluid ounce = 29.574 mL so to go from grams/cm 3 to dry ounces per fluid ounce, multiply by 0.9586.  


5 0
4 years ago
When 5.58g H2 react by the following balanced equation, 32.8g H2O are formed. What is the percent yield of the reaction? 2H2(g)+
8090 [49]

Answer:

D) 65.7%

Explanation:

Based on the reaction:

2H2(g)+O2(g)⟶2H2O(l)

<em>2 moles of hydrogen produce 2 moles of water assuming an excess of oxygen.</em>

<em />

To find percent yield of the reaction we need to find theoretical yield (The yield assuming all hydrogen reacts producing water). With theoretical yield and actual yield (32.8g H₂O) we can determine percent yield as 100 times the ratio between actual yield and theoretical yield.

<em>Theoretical yield:</em>

Moles of 5.58g H₂:

5.58g H₂ ₓ (1 mol / 2.016g) = 2.768 moles H₂

As 2 moles of H₂ produce 2 moles of H₂O, if all hydrogen reacts will produce 2.768 moles H₂O. In grams:

2.768 moles H₂O ₓ (18.015g / mol) =

49.86g H₂O is theoretical yield

<em>Percent yield:</em>

Percent yield = Actual yield / Theoretical yield ₓ 100

32.8g H₂O / 49.86g ₓ 100 =

65.7% is percent yield of the reaction

<h3>D) 65.7% </h3>

4 0
4 years ago
What is the amount in moles of a 52 g sample of aluminium fluoride, AIF3
Karo-lina-s [1.5K]

Answer:

Try looking for some kind of answer that has to do with .61904

Explanation:

52 g x 1 mol/ (molar mass of aluminum fluoride) 84 g = .619047619

Sorry if this is wrong but that's my best guess

6 0
3 years ago
In the third period of the periodic table, sodium is followed by magnesium, aluminum, silicon, and phosphorus. Which of these el
bagirrra123 [75]
Phosphorus has the smallest atomic size
7 0
4 years ago
In order to prepare very dilute solutions, a lab technician chooses to perform a series of dilutions instead of measuring a very
NeTakaya

Answer: 5.70\times 10^{-6}M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Given : 0.360 g of KNO_3 is dissolved in 500 ml of solution.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.360g}{101g/mol}=3.56\times 10^{-3}mole  

V_s = volume of solution  = 500 ml

Molarity=\frac{3.56\times 10^{-3}\times 1000}{500}=7.12\times 10^{-3}M

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 7.12\times 10^{-3}M

V_1 = volume of stock solution = 10.0 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 500.0 ml

7.12\times 10^{-3}M\times 10.0=M_2\times 500.0

M_2=1.42\times 10^{-4}M

b)  On further dilution

M_1 = molarity of stock solution = 1.42\times 10^{-4}M

V_1 = volume of stock solution = 10.0 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 250.0 ml

1.42\times 10^{-4}M\times 10.0=M_2\times 250.0

M_2=5.70\times 10^{-6}M

Thus the final concentration of the KNO_3 solution is 5.70\times 10^{-6}M

4 0
3 years ago
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