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Fiesta28 [93]
3 years ago
11

Rank the following in order of increasing (lowest to highest) reactivity:

Chemistry
1 answer:
choli [55]3 years ago
4 0

Answer:

a)  Li<Na<Rb

b) P<S

c) Rn<Xe

d) Hg<W<Cs

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What is the number of orbitals in an atom of radon
yan [13]
86 elections so 43 orbitals
6 0
3 years ago
Which element is classified as a noble gas?
Fed [463]

Answer:

Noble gas, any of the seven chemical elements that make up Group 18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og)

Explanation:

I found my answer on google

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6 0
3 years ago
An atom has an average atomic mass of about 63.5 amu. What is the chemical symbol for the atom? Consult the periodic table.
Mama L [17]
The best and most correct answer among the choices provided by your question is the fourth choice.

Copper <span>has an average atomic mass of about 63.5 </span>amu<span>.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
8 0
4 years ago
Read 2 more answers
HELP ME PLEASE!!!
krok68 [10]

Answer:

Br (Bromine)

H (Hydrogen)

Explanation:

7 0
4 years ago
A solution is prepared by dissolving 23.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the
alekssr [168]
<span>The density of the solution =1.05 g/ml.
</span><span>The total mass of the resulting solution is = 398.7 g (CaCl2 + water)
</span>
Find moles of CaCl2 and water.
Molar mass of CaCl2 = 110 (approx.)

Moles of CaCl2 = 23.7 / 110  = 0.22
so, moles of Cl- ion = 2 x 0.22 = 0.44  (because each molecule of CaCl2 will give two Cl- ions)
Moles of water = 375 / 18 = 20.83

Now, Mole fraction of CaCl2 =  (moles of CaCl2) / (total moles)

total moles = moles of Cl- ions + moles of Ca2+ ions + moles of water

                  = 0.44 + 0.22 + 20.83

=21.49


So, mole fraction = 0.44 / (21.49) = 0.02

Guess what !!! density is not used. No need

4 0
3 years ago
Read 2 more answers
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