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Fiesta28 [93]
3 years ago
11

Rank the following in order of increasing (lowest to highest) reactivity:

Chemistry
1 answer:
choli [55]3 years ago
4 0

Answer:

a)  Li<Na<Rb

b) P<S

c) Rn<Xe

d) Hg<W<Cs

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A gas in a rigid container at 25C has a pressure of .96atm. A change in temperature causes the pressure to increase to 1.25 atm.
mars1129 [50]
<h2>Hello!</h2>

The answer is:

The new temperature of the gas is equal to 388.22 K

<h2>Why?</h2>

Since we have a rigid container, we can safely assume that the volume is kept constant.

To solve the problem, we need to use the Gay Lussac's Law, which states that the pressure and the volume of an ideal gas are proportional  when the volume is kept constant.

Also, we need to remember that Gay Lussac's Law works with absolute temperature, so, we need to convert the given temperature (in celsius degrees) to Kelvin.

T(K)=273.15 + T(\°C)\\\\T(K)=273.15 +25=298.15K

So, using the Gay Lussac's equation, we have:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Where,

P_1 is equal to the first pressure.

T_1 is equal to the first temperature.

P_2 is equal to the new pressure.

T_2 is equal to the new temperature.

We are given the following information:

P_1=0.96atm

T_1=298.15K

P_2=1.25atm

Then, substituting and calculating, we have:

T_2=P_2*\frac{T_1}{P_1}\\\\T_2=1.25atm*\frac{298.15K}{0.96atm}=388.22K

Hence, the new temperature of the gas is equal to 388.22 K.

Have a nice day!

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