Question

In the balanced reaction below, what is the mole ratio comparing iron (Fe) and oxygen gas (O2)?

Answer 1

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Answer 2

The given balanced reaction is,

$4Fe(s) + 3O_{2}(g) --->2Fe_{2}O_{3} (s)$

The stoichiometric coefficients of each element or compound represents the number of moles of that element or compound required for the complete reaction to take place.

The mole ratios of different products and reactants will be:

$\frac{Fe}{O_{2}} = \frac{4 mol Fe}{3 mol O_{2}}$

$\frac{Fe}{Fe_{2}O_{3}} = \frac{4 mol Fe}{2 Fe_{2}O_{3}}$

$\frac{O_{2}}{Fe_{2}O_{3}} =\frac{3 mol O_{2}}{2molFe_{2}O_{3}}$

So the mole ratio comparing iron (Fe) and oxygen gas ($O_{2}$) is

4 : 3