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4 years ago

In the balanced reaction below, what is the mole ratio comparing iron (Fe) and oxygen gas (O2)?

Chemistry

2 answers:

Schach [20]4 years ago

8 0

Do you know the answers to this quiz?? I'm taking it right now

zepelin [54]4 years ago

5 0

The given balanced reaction is,

$4Fe(s) + 3O_{2}(g) --->2Fe_{2}O_{3} (s)$

The stoichiometric coefficients of each element or compound represents the number of moles of that element or compound required for the complete reaction to take place.

The mole ratios of different products and reactants will be:

$\frac{Fe}{O_{2}} = \frac{4 mol Fe}{3 mol O_{2}}$

$\frac{Fe}{Fe_{2}O_{3}} = \frac{4 mol Fe}{2 Fe_{2}O_{3}}$

$\frac{O_{2}}{Fe_{2}O_{3}} =\frac{3 mol O_{2}}{2molFe_{2}O_{3}}$

So the mole ratio comparing iron (Fe) and oxygen gas ( $O_{2}$ ) is

4 : 3

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3 years ago

A solution of NaCl (aq) is added slowly to a solution of lead nitrate, Pb(NO3)2 ( aq ), until no further precipitation occurs. T

Feliz [49]

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0.19615 M

Explanation:

Calculation of the moles of $PbCl_2$ as:-

Mass = 10.91 g

Molar mass of $PbCl_2$ = 278.1 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{10.91\ g}{278.1\ g/mol}$

$Moles= 0.03923\ mol$

According to the reaction shown below:-

$Pb(NO_3)_2_{(aq)} + 2NaCl_{(aq)}\rightarrow PbCl_2_{(s)} + 2NaNO_3_{(aq)}$

1 mole of $PbCL_2$ is produced when 1 mole of $Pb(NO_3)_2$ undergoes reaction.

0.03923 mole of $PbCL_2$ is produced when 0.03923 mole of $Pb(NO_3)_2$ undergoes reaction.

Mole of $Pb(NO_3)_2$ = 0.03923 mole

Volume = 200.0 mL = 0.2 L ( 1 mL = 0.001 L )

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$