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zlopas [31]
2 years ago
13

The day to day condition of atmosphere is known as

Chemistry
2 answers:
vovikov84 [41]2 years ago
5 0

Answer:

d) atmosphere pressure

Sphinxa [80]2 years ago
3 0

Answer:

B.) weather

Explanation:

weather is constantly changing everyday and each day presents a new condition:)

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Of the different states of matter listed below, which is typically the most dense?
stiv31 [10]
The correct answer is option B. The most dense phase of matter is the solid phase and the least dense are gases. However, there is an exception. Water is the exception. Solid water or ice is less dense than the liquid phase therefore it floats on liquid water.
7 0
3 years ago
Read 2 more answers
Determine the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C. Carry out two c
Nuetrik [128]

The pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.

<h3>How to calculate pressure?</h3>

The pressure of an ideal gas can be calculated using the following formula:

PV = nRT

Where;

  • P = pressure
  • V = volume
  • n = number of moles
  • R = gas law constant
  • T = temperature

According to information in this question;

  • T = 25°C = 25 + 273 = 298K
  • V = 244.6mL = 0.24L
  • R = 0.0821 Latm/Kmol

P × 0.24 = 1 × 0.0821 × 298

0.24P = 24.47

P = 24.47/0.24

P = 101.94atm

Therefore, the pressure in atm exerted by 1 mole of methane placed into a bulb with a volume of 244.6 mL at 25°C is 101.94atm.

Learn more about pressure at: brainly.com/question/11464844

3 0
2 years ago
Ca (ClO) 2<br> Spell out the full name of the compound.
antoniya [11.8K]
Calcium hypochlorite
5 0
3 years ago
What is the vapor pressure of CS2CS2 in mmHgmmHg at 26.5 ∘C∘C? Carbon disulfide, CS2CS2, has PvapPvap = 100 mmHgmmHg at −−5.1 ∘C
Digiron [165]

Answer: 26.5 mm Hg

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1= initial pressure at 26.5^oC = ?

P_2 = final pressure at -5.1^oC = 100 mm Hg

= enthalpy of vaporisation = 28.0 kJ/mol =28000 J/mol

R = gas constant = 8.314 J/mole.K

T_1= initial temperature = 26.5^oC=273+26.5=299.5K

T_2 = final temperature =-5.1^oC=273+(-5.1)=267.9K

Now put all the given values in this formula, we get

\log (\frac{P_1}{100})=\frac{28000}{2.303\times 8.314J/mole.K}[\frac{1}{299.5}-\frac{1}{267.9}]

\log  (\frac{P_1}{100})=-0.576

\frac{P_1}{100}=0.265

P_1=26.5mmHg

Thus the vapor pressure of CS_2CS_2 in mmHg at 26.5 ∘C is 26.5

7 0
3 years ago
1. An object was carefully weighed on three different balances. Each balance was zeroed
Hoochie [10]

Answer:

10.335

Explanation:

An object was carefully weighed on three different balances

Each of these balances were zeroed before weighing

The masses that were weighed are as follows

10.35 g , 10.355 g, 10.30 g

Therefore the average value of these measurements can be calculated as follows

The total number of mass is 3

= 10.30 + 10.355 + 10.30/3

= 31,005/3

= 10.335

Hence the average value of these measurements is 10.335

7 0
3 years ago
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