Answer:
The maximum height above the roof that the rock reaches is 7.6 meters.
Explanation:
Given that, a man stands on the roof of a building of height 14.0 m and throws a rock with a velocity of magnitude 26.0 m/s at an angle of 28 degrees above the horizontal.
It is assumed to find the maximum height above the roof that the rock reaches. Let it is given by y. So,
At maximum height, v = 0
Here, a = -g
y = 7.60 meters
So, the maximum height above the roof that the rock reaches is 7.6 meters. Hence, this is the required solution.
The formula for electric potential energy is given by:
where:
is the electric potential energy in Joules
is the Coulomb's constant 9×10⁹
and
are the amoun of charge
is the distance between the charges
we have:
= 4.5 × 10⁻⁵
= 2.0 × 10⁴
= 0.030
Substitute these values into the formula, we have:
Joules
Hydrogen (H)
Helium (He)
Lithium (Li)
Beryllium (Be)
Boron (B)
Carbon (C)
Nitrogen (N)
Oxygen (O)
Fluorine (F)
Neon (Ne)
Sodium (Na)
Magnesium (Mg)
Aluminum (Al)
Silicon (Si)
Phosphorus (P)
Sulfur (S)
Chlorine (Cl)
Argon (Ar)
Postassium(K)
Calcium(Ca)
I believe the answer is Mouse/Herbivore. It was a question in my old lab haha.
Hope this helped!!
~xox Melis
