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Butoxors [25]
3 years ago
8

Solve for c. a=1/5(b+c)a)c=a-5bb)c=5a-5bc)c=5b-ad)c=5a-b​

Mathematics
1 answer:
Ber [7]3 years ago
5 0

Option D is the answer.

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Solve for V . 7v-20=-6(v-1) Simplify your answer as much as possible.
Pavlova-9 [17]

Answer:

v = 2

Step-by-step explanation:

You can start by distributing -6:

7v - 20 = -6v + 6

To combine the like x terms, you can add 6v to both sides:

7v - 20 = -6v + 6

+6v          +6v

13v - 20 = 6

Now add 20 to both sides to isolate the x term:

13v - 20 = 6

      +20   +20

13v = 26

You can divide by 13 on both sides to find v,

13v = 26

÷13    ÷13

v = 2

7 0
3 years ago
Read 2 more answers
What is the domain of the given function?<br> {(3,-2), (6, 1), (-1, 4), (5, 9), (-4, 0)}
joja [24]

Answer:

The domain is {3,6,−1,5,−4}

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Do these questions, plz ☹️☹️
elena-s [515]
1.

He fills 5/6 lb per bag.
If he fills up 6 bags, he will use 6 * 5/6 lb = 5 lb.
Since he gets peanuts in 2-lb bags, he'd use 2 1/2 2-lb bags.
If he fills double that amount, 10 5/6-lb bags, he will use 10 lb of peanuts which is exactly 5 2-lb bags.
Answer: He should buy 5 2-lb bags.

2.

Each board has length x.
He cuts 3/5 of the length.
Each leftover piece is 2/5 of the length, or 2/5 x.
When he puts together several of the leftover pieces, he has 4 times the length of the original board, or 4x.
4x/(2/5 x) = 4x * 5/2 x = 10x

He has cut 10 boards.
5 0
4 years ago
Helppp!!! Will fan and Medal!!!
Bond [772]
Let n = 0, 1, 2, 3, 4, 5, 6, 7.... 
When n = 0 then 0^2 + 0 = 0. n = 1 we have 1^2 + 1 = 2. And when n = 2 we have 2^2 + 2 = 6. When n= 3 we have 3^2 + 3 = 12. When n = 4 we have 4^2 + 4 = 20. When n = 5 we have 5^2 + 5 = 30. When n = 6 = 6^2 + 6 = 42. And finally when n = 7 we have 7^2 + 7 = 56. So at n = 1, 2, ...7, ... Our values are = 2, 6, 12, 20, 30, 42, and 56. It is obvious that n is always an even number. Hence n^2 + n is always an even integer for all positive integers. 
When n = -1 we have (-1)^2 - 1 = 0 when n = -2 we have (-2)^2 -2 = 2. When n = -3 we have (-3)^2 - 3 = 6. When n = -4 we have (-4)^2 - 4 = 16 - 4 =12. When n =-5 we have (-5)^2 -5 = 20. When n = -6 we have (-6)^2 - 6 = 30. When n = (-7)^2 - 7 = 42. Hence n^2 + n is always even for all integers
4 0
4 years ago
Andre likes a hot cocoa recipe with 1 cup of milk and 3 tablespoons of cocoa. He poured 1 cup of milk but accidentally added 5 t
garik1379 [7]
What's the question?
4 0
3 years ago
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