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spin [16.1K]
3 years ago
6

Hydrogen is a reactive gas under normal conditions.Based on this property alone, to which group of the periodic table should hyd

rogen belong?why?
Chemistry
2 answers:
Greeley [361]3 years ago
8 0
Even if hydrogen is in 1 group originally you can still say it is in 6 groups.
denis23 [38]3 years ago
5 0
Even though Hydrogen is originally in group 1, based on this property, we can say it is in group 6.

Because:

Group 6 would mean that it only needs 2 more valence electrons till the octet (8 valence electrons). This would make it reactive, yet, in normal conditions, unlike group 7.
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Which compound is produced during regeneration?
abruzzese [7]

The answer is RuBP.

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Calvin Cycle consists of three stages:
1. fixation: the enzyme RuBisCO incorporates (fixes) carbon-dioxide into 3-PGA.
2. reduction: 3-PGA is reduced using NADPH as electron supply.
<span><u>3. regeneration: RuBP is regenerated and starts the cycle again.</u></span></span>

8 0
3 years ago
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Temperature is used to measure the movement of particles such as atoms and molecules. As temperature increases, what is true of
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4 mol of water is made up of 2.408×10^24 molecules of water.
zhenek [66]
It would be 20 give me bravest
6 0
3 years ago
Elements in the same period share the same number of:
Anuta_ua [19.1K]

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7 0
2 years ago
2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent y
Elden [556K]

Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

<em>Moles Fe -Molar mass: 55.845g/mol-:</em>

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.

As there are 14.8 moles of the acid, <em>Fe is limiting reasctant.</em>

The moles of H2 produced are:

0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2

The mass is:

0.277 moles H2 * (2.016g/mol) = 0.558g H2

Percent yield is:

5.40g / 0.558g * 100 = 1040%

It is possible the experiment wasn't performed correctly

7 0
2 years ago
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