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Studentka2010 [4]
3 years ago
10

Where do we use controlled fission?

Chemistry
1 answer:
sukhopar [10]3 years ago
3 0

Answer: Uranium and plutonium are most commonly used to control fission

Explanation:

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In the first 85.0 s of this reaction, the concentration of no dropped from 1.12 m to 0.520 m . calculate the average rate of the
goldenfox [79]

In the first 85.0 s of this reaction, the concentration of no dropped from 1.12 m to 0.520 m .

What is rate of a reaction?

The speed at which a chemical reaction takes place is the rate of the reaction. It is the concentration change per unit time of a reactant in a reaction.

Since the concentration of NO reduces to half its initial concentration in 85 seconds that is from 1.12m to 0.520m, it can be said that 85 seconds is the half life interval for the reaction, <u>Hence on average, </u><u>half reaction</u><u> is completed in the time interval of </u><u>85 seconds</u><u>.</u>

To learn more about rate of a reaction from the given link below,

brainly.com/question/12172706

#SPJ4

7 0
2 years ago
A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera
Grace [21]

Answer: The initial temperature of the iron was 515^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of iron = 360 g

m_2 = mass of water = 750 g

T_{final} = final temperature = 46.7^0C

T_1 = temperature of iron = ?

T_2 = temperature of water = 22.5^oC

c_1 = specific heat of iron = 0.450J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]

T_i=515^0C

Therefore, the initial temperature of the iron was 515^0C

4 0
3 years ago
18.2 mL of a 0.156 M solution of lead(II) nitrate are added to 26.2 mL of a 0.274 M solution of potassium iodide.
kow [346]

The mass of the Pbl2 : 1308.87

<h3>Further explanation</h3>

Given

18.2 mL of a 0.156 M Pb(NO3)2

26.2 mL of a 0.274 M KI

Reaction

Pb(NO3)2 (aq) + 2 KI (aq) - Pbl2 (s) + 2 KNO3

Required

the mass of the Pbl2

Solution

mol Pb(NO3)2 = 18.2 x 0.156 = 2.8392 mlmol

mol KI = 26.2 x 0.274 =7.1788 mol

Limiting reactant Pb(NO3)2(smaller ratio of mol : reaction coeffiecient)

mol Pbl2 based on limiting reactant (Pb(NO3)2)

From equation, mol ratio of Pb(NO3)2 : Pbl2 = 1 : 1, so mol Pbl2=mol Pb(NO3)2=2.8392

Mass Pb(NO3)2 :

\tt mass=mol\times MW\\\\mass=2.8392\times 461\\\\mass=1308.87~grams

5 0
3 years ago
An object has________when it has been stretched or compressed
Alina [70]

Answer:

Elasticity or Flexibility

Explanation:

The ability of an object to resume its normal shape after being stretched or compressed is called elasticity

4 0
3 years ago
Which statement describes the use of a flowchart?
Crazy boy [7]

Answer:

idk i got 0 iQ

Explanation:

4 0
3 years ago
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