Answer:
The speed of the soccer ball at height point is less than its initial speed
Explanation:
The initial velocity of the soccer can be written in vector form as
= v cos θ î + v sin θ j
where is initial velocity of the ball
v is the initial speed of the ball
Assume soccer ball is kicked at an angle θ with an horizontal and initial speed vm/s. Its horizontal component will be as,
= v cos θ
= v sin θ
At the maximum height, the vertical component becomes zero. therefore, the velocity of the soccer at the maximum point can be written as,
= v cos θ j
where, is velocity of the soccer ball at maximum height
Answer:
there are 5 hydrogen atoms in that formula
Answer:
the distance of the top of the window below the windowsill from which the flowerpot fell is 0.31 m
Explanation:
given information:
time, t = 0.420 s
height, h = 1.9 m
the the vertical motion equation:
h = 
t + 
where
h = height (m)
= initial velocity (m/s)
t = time (s)
g = gravitational force (9.8 
)
first we calculate the velocity of the flowers pot when it reaches top window
h = t +
1.9 = (0.42) + (
)
= (1.9 - ())/0.42
= 2.47 m/s
now we can find the distance of the windowsil
+ 2gh
v = 0, thus
2gh = - 
h = -/2g
= 
/ (2 x 9.8)
= 0.31 m
To solve this problem we will start from the definition of energy of a spring mass system based on the simple harmonic movement. Using the relationship of equality and balance between both systems we will find the relationship of the amplitudes in terms of angular velocities. Using the equivalent expressions of angular velocity we will find the final ratio. This is,
The energy of the system having mass m is,
The energy of the system having mass 2m is,
For the two expressions mentioned above remember that the variables mean
m = mass
Angular velocity
A = Amplitude
The energies of the two system are same then,
Remember that
Replacing this value we have then
But the value of the mass was previously given, then
Therefore the ratio of the oscillation amplitudes it is the same.
