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maria [59]
3 years ago
12

A step-down transformer has 2500 turns on its primary and 5.0 x 10' tums on its secondary. If the potential difference across th

e primary is 4850 V, what is
the potential difference across the secondary?
Physics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer:

I dont know sorry

Explanation:

hehe

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If a resistance is added in parallel to a circuit resistance is than?
irakobra [83]

Answer: The total resistance in a parallel circuit is always less than any of the branch resistances. Adding more parallel resistances to the paths causes the total resistance in the circuit to decrease. As you add more and more branches to the circuit the total current will increase because Ohm's Law states that the lower the resistance, the higher the current.

Explanation:

8 0
3 years ago
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Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at po
Lerok [7]

Answer:

h = 1.75 m

Explanation:

As we know that height of the slide is given as

h = 1.80 m

so time taken by the child to hit the water from the slide is given as

t = \sqrt{\frac{2h}{g}}

now we will plug all data in it

t = \sqrt{\frac{2(1.80)}{9.81}}

t = 0.605 s

now we know that the horizontal distance moved by it is given as

L = v_x t

3.55 = 0.605 v_x

v_x = 5.86 m/s

now by energy conservation

mgh = \frac{1}{2}mv^2

so height of point A is given as

h = \frac{v_x^2}{2g}

h = \frac{5.86^2}{2(9.81)}

h = 1.75 m

3 0
3 years ago
A super snail initially traveling at 2 m/s accelerates at 1 m/s^2 for 5 seconds. How fast will it be going at the end of the 5 s
Vedmedyk [2.9K]

Answer:

The snail travel at the end of 5 s with a velocity of 12 m/s and the distance of the snail is 22.5 m.

Explanation:

Given that, the initial velocity of the snail is,

u=2m/s

And the acceleration of the snail is,

a=1m/s^{2}

And the time taken by the snail is,

t=5 sec

Now according to first equation of motion,

v=u+at

Here, u is the initial velocity, t is the time, v is the final velocity and a is the acceleration.

Now substitute all the variables

v=2m/s+ 1 \times 5 sec\\v=7m/s

Therefore, the snail travel at the end of 5 s with a velocity of 7 m/s.

Now according to third equation of motion.

v^{2}- u^{2}=2as\\ s=\frac{v^{2}- u^{2}}{2a} \\

Here, u is the initial velocity, a is the acceleration, s is the displacement, v is the final velocity.

Substitute all the variables in above equation.

s=\dfrac{7^{2}- 2^{2}}{2(1)}\\s=\dfrac{45}{2}\\ s=22.5m

Therefore the distance of the snail is 22.5 m.

4 0
3 years ago
A 3.00 kg box is lifted by an upward force 1.50 m above the surface pf Earth to the top of a table. What is the potential energy
Allushta [10]
The potential energy is 45J(joules)
5 0
3 years ago
consider a charged parallel-plate capacitor. which combination of changes would quadruple its capacitance?
kogti [31]

Its capacitance Double the charge and double the plate area.

Doubling the distance between the plates of a capacitor double the capacitance. Doubling the distance between the plates of a capacitor quadruples the capacitance. As the distance between the plates decreases, the capacitance increases because the potential difference decreases.

Halving the distance between the plates of a parallel plate capacitor doubles the capacitance of the capacitor from its initial capacitance. When two or more capacitors are connected in parallel, the overall effect is that of a single equivalent capacitor with the sum of the plate areas of the individual capacitors. As we saw earlier all other factors being equal, more disk space equals more capacity.

Learn more about Capacitor here:-brainly.com/question/27393410

#SPJ4

4 0
1 year ago
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